Answer:
The probability of 1 or less children from that group to learn how to swim before 6 years of age is 0.072
Step-by-step explanation:
In this case we need to compute the probability of none of these 12 children learns to swim before 6 years of age. This is given by:
p(0) = (1 - 0.312)^(12) = 0.688^(12) = 0.01124
We now need to calculate the probability that one child learns to swim before 6 years of age.
p(1) = 12*0.312*(1 - 0.312)^(11) = 3.744*(0.688)^(11)
p(1) = 3.744*0.01634
p(1) = 0.0612
The probability of 1 or less children from that group to learn how to swim before 6 years of age is:
p = p(0) + p(1) = 0.01124 + 0.0612 = 0.07244
Answer:
○ b Parallel
Step-by-step explanation:
If you take a look at each group of coefficients [2x and 5y, 4x and 10y], they have a proportional relationship, so when converting from <em>Linear Standard Form</em> to <em>Slope-Intercept</em><em> </em><em>Form</em>,<em> </em>they will always have an exact same <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] of −⅖.
I am joyous to assist you anytime.
Answer: 
Step-by-step explanation:
Given : The number of cherry lollipop = 5
The total number of lollipop = 8
the number of lollipops other than grape =6
The probability of selecting a cherry lollipop is given by :_
The probability of selecting a lollipop other than grape is given by :_
Since, there is replacement , then the events are independent of each other.
Now, the probability that Julie will select a cherry lollipop and then a lollipop other than grape is given by :-
Hence, the required probability =
I believe the answer is 8♀️
<h3>
Answer: x = 29</h3>
========================================================
Work Shown:
A = 2x+3
B = x
angles A and B are complementary, so they add to 90 degrees
A+B = 90
(2x+3)+(x) = 90
2x+3+x = 90
2x+x+3 = 90
3x+3 = 90
3x+3-3 = 90-3
3x = 87
3x/3 = 87/3
x = 29
Extra info:
2x+3 = 2(29)+3 = 58+3 = 61
Note that 29 and 61 add to 29+61 = 90
