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Ksivusya [100]
3 years ago
14

Can anybody help me please

Mathematics
2 answers:
Advocard [28]3 years ago
8 0

Answer:

Is B

Step-by-step explanation:

Maslowich3 years ago
7 0

Answer:

      B

Step-by-step explanation:

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The ordered pairs in the table below represent a linear function.
EastWind [94]

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3 years ago
Which relation is also a function?​
Solnce55 [7]

Answer:

C.

Step-by-step explanation:

For a relation to be considered a function, all x-coordinates must be different.

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If the radius of a circle is 3cm wht is the area of the circle
Ludmilka [50]
The Formula would be A=3.14rr
Which is A=3.14(3)(3)
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5 0
3 years ago
Read 2 more answers
92+ 56/14−x =100. <br> Plz answer fast
Vladimir79 [104]

Step-by-step explanation:

don't forget about PEMDAS

Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction

first you're going to want to do 56 / 14.

4 0
4 years ago
In 1998 there were 1509 daily newspapers in the country. By 2003​, there were only 1454 daily newspapers.
natta225 [31]

Answer:

<em>The number of daily newspapers in 2000 is estimated in 1487</em>

Step-by-step explanation:

<u>Modeling Functions </u>

Real-world situations are often modeled with mathematic functions. Functions allow making predictions and analysis to better understand and manage those situations

a. In our example, we know that in 1998 there were 1509 daily newspapers in the country. It gives us a starting point (0,1509), where the first coordinate is the years after 1998 and the second is the number of daily newspapers. The second point comes from the next data: by 2003 (5 years after 1998), there were 1454 daily newspapers. The new point is (5,1454).

b. Knowing the relationship between years after 1998 and the numbers of daily newspapers is linear, we can construct the function by using both points. The equation of a line, given the points (a,b) and (c,d) is

\displaystyle y-b=\frac{d-b}{c-a}(x-a)

Where y is the number of daily newspapers and x is the number of years after 1998. Using the given points, we have

\displaystyle y-1509=\frac{1454-1509}{5-0}(x-0)

\displaystyle y-1509=-11(x-0)

\displaystyle y-1509=-11x

y=1509-11x

c. We can use the above relationship to estimate the number of daily newspapers in 2000. For this year, x=2, thus

y=1509-11(2)=1487

The number of daily newspapers in 2000 is estimated in 1487

7 0
3 years ago
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