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3 years ago

Please tell me the answer

Mathematics

2 answers:

VikaD [51]3 years ago

7 0

Answer:

<h2>It shifts left</h2>

I hope this helps you with your algebra

Sedaia [141]3 years ago

4 0

To my calculations the anwser is it shifts left

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the two fastest times in the past 20 years for the girls 200 meter run at clarksville elementary school are 27.97 sec and 27.93

nlexa [21]

Her time was 0.02 seconds short of being equal to the 2nd fastest time. In conclusion, no, she was slower.

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2 years ago

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The scale model of a rectangular patio will be enlarged by a scale factor of 2.5 to create the actual patio. The actual patio wi

cricket20 [7]

Step-by-step explanation:

Below is an attachment containing the solution.

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Theresa has two brothers, Paul and Steve, who are both the same height. Paul says he is

Schach [20]

Answer:

From given, we have,

Paul says he is 16 inches shorter than 1 1/2 times Theresa's height.

Steve says he's 6 inches shorter than 1 1/3 times Theresa's height.

Let the height of Theresa be "x" inches.

So, we get,

For Paul, 1 1/2 x - 16 = T

⇒ 3/2 x - 16 = T ......(1)

For Steve, 1 1/3 x - 6 = T

⇒ 4/3 x - 6 = T .........(2)

equating equations (1) and (2), we get,

3/2 x - 16 = 4/3 x - 6

6 - 16 = 4/3 x - 3/2 x

-10 = (8 - 9)/6 x

-60 = -x

x = 60 inches.

Therefore, Theresa is 60 inches tall.

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2 years ago

Suppose a population of honey bees in Ephraim, UT has an initial population of 2300 and 12 years later the population reaches 13

Rama09 [41]

Answer:

common ratio: 1.155

rate of growth: 15.5 %

Step-by-step explanation:

The model for exponential growth of population P looks like: $P(t)=P_i(1+r)^t$

where $P(t)$ is the population at time "t",

$P_i$ is the initial (starting) population

$(1+r)$ is the common ratio,

and $r$ is the rate of growth

Therefore, in our case we can replace specific values in this expression (including population after 12 years, and initial population), and solve for the unknown common ratio and its related rate of growth:

$P(t)=P_i(1+r)^t\\13000=2300*(1+r)^{12}\\\frac{13000}{2300} = (1+r)^12\\\frac{130}{23} = (1+r)^{12}\\1+r=\sqrt[12]{\frac{130}{23} } =1.155273\\$

This (1+r) is the common ratio, that we are asked to round to the nearest thousandth, so we use: 1.155

We are also asked to find the rate of increase (r), and to express it in percent form. Therefore we use the last equation shown above to solve for "r" and express tin percent form:

$1+r=1.155273\\r=1.155273-1=0.155273$