Pick any point and then plug the domain and range into x (domain value) and y (range value).
So if the measure of angle AMB = 90 so the another right triangle is formed which is ADM, since the it is a right triangle the legs are equal, then the lenght AD = DM and we can solve the length of AM
AM = sqrt( AD^2 + DM^2)
AM = sqrt( 6^2 + 6^2)
AM = 6sqrt(2)
now we can solve the length of AB
AB = sqrt ( AM^2 + MB^2)
AB = sqrt ( 6sqrt(2)^2 + 6sqrt(2)^2)
AB = 12
so the perimeter = 2(6) + 2(12) = 36
Let the width be x.
width = x
length = x + 8
The area is 20 ft²
x(x + 8) = 20
x² + 8x = 20
x² + 8x - 20 = 0
(x + 10) (x - 2) = 0
x = -10 (rejected) or x = 2
Width = x = 2 ft
Length = x + 8 = 2 + 8 = 10 ft
Answer: The width is 2 ft and the length is 10ft.
The answer to #1 is b.600 and the answer to #2 is 2,132
Answer:
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