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NARA [144]
2 years ago
5

A bicycle manufacturing company makes a particular type of bike. Each child bike requires 4 hours to build and 4 hours to test.

Each adult bike requires 6 hours to build and 4 hours to test. With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week. If c represents child bikes and a represents adult bikes, determine which system of inequality best explains whether the company can build 20 child bikes and 6 adult bikes in the week. (2 points)
Mathematics
1 answer:
nikitadnepr [17]2 years ago
7 0

Answer:

4 (20) + 6(6) = 120

4(20) + 4 (6) = 100

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations with the information given:

Build time (hours) = 4c + 6a = 120

Test time (hours) = 4c + 4 a = 100

Where c represents the number of child bikes and a represents adult bikes.

So, for 20 child bikes and 6 adult bikes:

4 (20) + 6(6) = 120

4(20) + 4 (6) = 100

Feel free to ask for more if needed or if you did not understand something.

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Angle A and angle B are complementary angles. If m∡a = 4x and m∡b = 3x +13, what is the measure of the smaller angle?
bagirrra123 [75]

Answer:

Step-by-step explanation:

Complementary angles mean two two angles sum with equal 90 degrees. Therefore you would need to create an equation to solve for the value of x.

4x+3x+13=90

-13 -13

7x=77

/7 /7

X=11

Now plug in the value of x.

A=4(11) B=3(11)+13

A=44. B=33+13

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5 0
2 years ago
X/2+1=6 i need help please
jasenka [17]

Answer:

x = 10

Step-by-step explanation: 10/2 = 5 + 1 = 6

8 0
2 years ago
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<img src="https://tex.z-dn.net/?f=%28%20%5Csin%5E%7B2%7D%20%28%20%5Cfrac%7B%5Cpi%7D%7B%204%20%7D%20%20-%20%20%5Calpha%20%29%20%2
guapka [62]

Step-by-step explanation:

\sin^2 (\frac{\pi}{4} - \alpha) = \frac{1}{2}(1 - \sin 2\alpha)

Use the identity

\sin^2 \theta = \dfrac{1 - \cos 2\theta}{2}

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\dfrac{1 - \cos [2(\frac{\pi}{4} - \alpha)]}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\dfrac{1 - \cos (\frac{\pi}{2} - 2\alpha)}{2} = \frac{1}{2}(1 - \sin 2\alpha)

Now use the identity

\sin \theta = \cos(\frac{\pi}{2} - \theta)

on the left side.

\dfrac{1 - \sin 2\alpha}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\frac{1}{2}(1 - \sin 2\alpha) = \frac{1}{2}(1 - \sin 2\alpha)

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2 years ago
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