Answer:
Takeru bought 72 eggs and baked 18 soufflés .
Step-by-step explanation:
Let
e = number of eggs Takeru bought.
s = number of soufflés Takeru bought.
Then we know that Takeru bought 4 times as many eggs as he baked soufflés, therefore:

And since for every soufflés Takeru bakes he uses 3 eggs, and after backing he has 18 eggs left, we have:
<em>This says that from
eggs there are 18 eggs left after Tkeru used three eggs for each soufflé.</em>
Now we have two equations:


We put the value of e from equation (1) into equation (2) and solve for s and get:


Thus
Number of eggs Takeru bought = 72.
Number of soufflés Takeru bought = 18.
Answer:
216π in²
Step-by-step explanation:
Base area = π × r²
36 π = π × r²
r² = 36
r = 6
Volume = base area × height
432 π = 36 π × height
height = 12
Surface area:
2 × π × r × (r + h)
2π × 6 × (6 + 12)
216π
Answer: 0.567
Step-by-step explanation:

Answer:<span> =<span><span><span><span><span>x4</span>+<span>15<span>x3</span></span></span>−<span>77<span>x2</span></span></span>+<span>14x</span></span>−<span>40</span></span></span>