There are 10,000 total four-digit numbers (1000 through 9999).
Multiples of 2 end in 0, 2, 4, 6, and 8. There are 9*10*10*5 = 4500 four-digit multiples of 2.
Multiples of 5 end in 0 or 5. There are 9*10*10*2 = 1800 four-digit multiples of 5.
There is redundancy between the two sets of numbers, namely those that end in 0, which are both multiples of 2 and 5. There are 9*10*10*1 = 900 four-digit multiples of both 2 and 5.
Then there are 4500 + 1800 - 900 = 5400 total four-digit numbers that are either multiples of 2 or 5, which means the remaining 4600 numbers are neither multiples of 2 nor 5.
Answer:
$241009.50
Step-by-step explanation:
35.50*3247=115268.50
35.50*3542=125741.00
+________
241009.5
Answer:
S44.10
Step-by-step explanation:
20% of 52 is 41.6
6% of 41.6 is 2.49600 US$ which rounds to 2.50
2.50+41.6=44.1
$44.10
Answer:
z=34
Step-by-step explanation:
2 + 8 - z = -24
add
10-z = -24
subtract 10 from each side
10-z-10 = -24-10
-z = -34
multiply by -1
-1*-z = -34 * -1
z = 34
