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adell [148]
3 years ago
10

What is the distance between the two points (-8,-6) and (-2,4)?

Mathematics
1 answer:
MAVERICK [17]3 years ago
6 0

Answer:

\sqrt{136} = 11.66 units

Step-by-step explanation:

distance between 2 points (a,b) and (c,d) = \sqrt{(a^{2}-c^{2} ) +(b^{2}-d^{2} ) }

= \sqrt{((-8)^{2}-(-2)^{2} ) + ((-6)^{2}-4^{2})   }

=\sqrt{136}

= 11.66 units

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const2013 [10]

<em>y</em> - 1/<em>z</em> = 1   ==>   <em>y</em> = 1 + 1/<em>z</em>

<em>z</em> - 1/<em>x</em> = 1   ==>   <em>z</em> = 1 + 1/<em>x</em>

==>   <em>y</em> = 1 + 1/(1 + 1/<em>x</em>) = 1 + <em>x</em>/(<em>x</em> + 1) = (2<em>x</em> + 1)/(<em>x</em> + 1)

<em>x</em> - 1/<em>y</em> = <em>x</em> - (<em>x</em> + 1)/(2<em>x</em> + 1) = (2<em>x</em> ² - 1)/(2<em>x</em> + 1) = 1

==>   2<em>x</em> ² - 1 = 2<em>x</em> + 1

==>   2<em>x</em> ² - 2<em>x</em> - 2 = 0

==>   <em>x</em> ² - <em>x</em> - 1 = 0

==>   <em>x</em> = (1 ± √5)/2

If you start solving for <em>z</em>, then for <em>x</em>, then for <em>y</em>, you would get the same equation as above (with <em>y</em> in place of <em>x</em>), and the same thing happens if you solve for <em>x</em>, then <em>y</em>, then <em>z</em>. So it turns out that <em>x</em> = <em>y</em> = <em>z</em>.

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2 years ago
If Gabby wants to make a regular octagon with a side length of 20 inches using a wire how much wire does she need? Justify your
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Answer: 160 inches.

Step-by-step explanation:

If an octagon has 8 sides and the side length is 20 inches, 20 x 8 = 160 inches. That means she needs 160 inches of wire.

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3 years ago
-11 X +4+ 8X -4+ 3X equals
maksim [4K]

Answer:

0

Step-by-step explanation:

First what you want to do is add together the common numbers

So, take all of the X's and add them together

(-11, 8, and 3)

-11x + 8x + 3x

-3x + 3x

0

So that all evens out

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4 - 4

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This equation equals 0

Hope this helps!!!

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3 years ago
Read 2 more answers
Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.
Sindrei [870]

Answer:

a) P(X=3) = 0.1

b) P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

c) P(X=4) = 0.3

d) P(X=0) = 0.2

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And replacing we got:

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And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

Step-by-step explanation:

We have the following distribution

x      0     1     2   3   4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

P(X=3) = 0.1

Part b

We want this probability:

P(X\geq 3) =1-P(X

And replacing we got:

P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4

Part c

For this case we want this probability:

P(X=4) = 0.3

Part d

P(X=0) = 0.2

Part e

We can find the mean with this formula:

E(X)= \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2

Part f

We can find the second moment with this formula

E(X^2)= \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4

And the variance would be:

Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4

And the deviation:

\sigma =\sqrt{2.4} = 1.549

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3 years ago
Weights of babies at the local community hospital have a distribution that is approximately normal with a mean weight of 7.43 po
KengaRu [80]

Answer:

Step-by-step explanation:

Hope this helped

4 0
3 years ago
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