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Darina [25.2K]
3 years ago
10

Quadrilaterals must have exactly 4 sides. The shapes in ___ must have 2 pairs of parallel sides, 4 right angles, and 4 sides of

equal length. The shapes in ___ must have at least one pair of parallel sides. The shapes in Group D must have 2 pairs of parallel sides and 4 sides of equal length. The shapes in ___ must have 2 pairs of parallel sides and 4 right angles. The shapes in ___ must have exactly 2 pairs of parallel sides.
Mathematics
2 answers:
QveST [7]3 years ago
7 0

Answer:

yoooo

Step-by-step explanation:

dem82 [27]3 years ago
4 0

Answer:

1) Square

2) Trapezoid

3) Rectangle

4) Parallelogram

Step-by-step explanation:

Quadrilaterals must have exactly 4 sides.

The shapes in a square must have 2 pairs of parallel sides, 4 right angles, and 4 sides of equal length.

The shapes in a trapezoid must have at least one pair of parallel sides. The shapes in Group D must have 2 pairs of parallel sides and 4 sides of equal length.

The shapes in a rectangle must have 2 pairs of parallel sides and 4 right angles.

The shapes in Parallelogram must have exactly 2 pairs of parallel sides.

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What is the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compare
Elena-2011 [213]

Answer:

38.9 square inches.

Step-by-step explanation:

We are asked to find the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compared to a pair of 5 inch wipers operating together each having a central angle of 114 degrees.

We will use area of sector formula to solve our given problem as:

\text{Area of sector}=\frac{\theta}{360}\times \pi r^2, where, r represents radius and theta represents central angle.

Let us find area of sector with central angle 140 degree and radius 3 inch.

\text{Area of sector}=\frac{138}{360}\times \pi (3)^2

\text{Area of sector}=\frac{138}{360}\times 9\pi

\text{Area of sector}=10.83849

Now, we will find area of sector with central angle 114 degree and radius 5 inch and multiply by 2 as:

\text{Area of sector}=2(\frac{114}{360}\times \pi (5)^2)

\text{Area of sector}=2(\frac{114}{360}\times 25\pi)

\text{Area of sector}=\frac{114}{360}\times 50\pi

\text{Area of sector}=49.74188

Let us find difference of area as shown below:

\text{Difference of areas}=49.74188-10.83849

\text{Difference of areas}=38.90339

\text{Difference of areas}\approx 38.9

Therefore, the difference in area covered is approximately 38.9 square inches.

8 0
3 years ago
Triangle DEF is congruent to GHJ by the SSS theorem. Which rigid transformation is required to map DEF onto GHJ?
kondaur [170]

Answer: The correct option is 4, i.e., translation.

Explanation:

It is given that the triangle DEF is congruent to GHJ by the SSS theorem.

From the given figure it is noticed that the triangle DEF and GHI are isosceles triangle.

Reason for correct option:

In transition the side and angles of the shape are not effected and the figure transfers from one place to another place without making any other change.

Since the both triangle are congruent and the position of all sides and angles are same, therefore option 4 is correct.

Reason for incorrect option:

In dilation the size of the figure is either stretched or compressed according to the scale factor k. But in the given figure the size of both triangles are same it means option A is incorrect.

In reflection the distance of all the point in preimage and all the image are same from the central line. Any central line does not exist in given figure. SO, the option B is incorrect.

In rotation the side length and angles are not affected but the position are not same, therefore the option C is incorrect.

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4 years ago
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Answer:

t >590

Step-by-step explanation:

t has to be greater than (>) 590.

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