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goldfiish [28.3K]
2 years ago
6

100-(2 8/5+1 3/8)×(3.05-0.8

Mathematics
1 answer:
Leya [2.2K]2 years ago
5 0
<span>88.80625 is the answer because I used a calculator.</span>
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PLEASE HELP URGENTTT
Margaret [11]

Answer: g^2+2g+1

Step-by-step explanation: Since she wants each side to be 1 inch larger, each side has a length of g+1. You need to find the area by squaring (g+1).

Write this as (g+1)(g+1). Use the FOIL method to get g^2+g+g+1. Simplify this to g^2+2g+1.

3 0
2 years ago
Read 2 more answers
Find the perimeter of the isosceles triangle with points A (0,0); B (3,3); and C (6,0)
finlep [7]

Answer:

use distance formula for the sides of the triangle

6 0
2 years ago
Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3
aliina [53]

Answer:

C) more than the absolute value of the critical value, we can conclude that the average monthly rate for an assisted-living facility is not equal to $3,300.

Step-by-step explanation:

Hello!

Interest hypothesizes is " the average monthly rate for one-bedroom assisted-living facility is equal to $3300" symbolically: μ = 3300

The study variable is:

X: Monthly rate for a one-bedroom assisted-living facility.

Since there is no information about the distribution of the variable, to be able to study the population mean, I'll assume that the variable has a normal distribution.

The hypothesis is:

H₀: μ = 3300

H₁: μ ≠ 3300

α: 0.05

The statistic to use, considering that there is no known population information and the sample size, is a Student t:

t= <u> X[bar] - μ </u> ~t_{n-1}

       S/√n

n= 12

X[bar]= $3690

S= $530

Using the sample data, calculate the statistic value:

t= <u> 3690 - 3300 </u> = 2.549

       530/√12

The rejection region for this test is two-tailed, with critical values:

t_{n-1; \alpha /2} = t_{11; 0.025} = -2.201

t_{n-1;1-\alpha /2} = t_{11; 0.975} = 2.201

The decision rule is:

Reject the null hypothesis if t ≤ -2.201 or if t ≥ 2.201

Not reject the null hypothesis if -2.201 < t < 2.201

Since the calculated value (2.549) is greater than the right critical value (2.201) the decision is to reject the null hypothesis.

With a signification level of 5%, there is enough evidence to reject the null hypothesis. This means that the population mean of the monthly rate for a one-bedroom assisted living facility is different from $3300.

I hope it helps!

7 0
2 years ago
Use the method of reduction of order to find a second independent solution of the given differential equation. t2y'' + 3ty' + y
Charra [1.4K]

I assume you mean y_1=t^{-1}, and not y_1=t-1, since this doesn't satisfy the ODE.

Assume a second solution of the form y_2=vy_1, where v is a function of t. Then

{y_2}'=v'y_1+v{y_1}'

{y_2}''=v''y_1+2v'{y_1}'+v{y_1}''

Substituting into the ODE gives

t^2\left(\dfrac{v''}t-\dfrac{2v'}{t^2}+\dfrac{2v}{t^3}\right)+3t\left(\dfrac{v'}t-\dfrac v{t^2}\right)+\dfrac vt=0

\implies tv''+v'=0

\implies(tv')'=0

\implies tv'=C

\implies v'=\dfrac Ct

\implies v=C_1\ln|t|+C_2

\implies y_2=\dfrac{\ln t}t

where we omit the second term because it's already accounted for by y_1.

3 0
3 years ago
Write each power as a product of the Same factor then find the value 1. 4^3 2. 2^6 3. 8^4 4. 12^2​
qwelly [4]

Answer:

15^3=15×15×15=3375

0^4=0×0×0×0=0

5^5=5×5×5×5×5=3125

3.5^2=3.5×3.5=12.25

6^5=6×6×6×6×6=7776

7^4=7×7×7×7=2401

1^8=1×1×1×1×1×1×1×1=1

2.5^3=2.5×2.5×2.5=15.625

Step-by-step explanation:

7 0
2 years ago
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