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docker41 [41]
3 years ago
6

James multiplies 38 by 55. He finds three of the four partial products: 40, 150, and

Mathematics
1 answer:
Nuetrik [128]3 years ago
8 0
The answer is one thousand five hundred thirty eight
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Find the area of each figure below
Ugo [173]

Answer:

25. 27a^{3}b^{2}

26. 3\pi x^{3}y

Step-by-step explanation:

For 25:

A = \frac{a+b}{2} h  (area of a trapezoid)

A=\frac{11a^{2}b+7a^{2}b}{2} *3ab  (substitute terms)

= \frac{18a^{2}b}{2}*3ab  (collect like terms)

= 9a^{2}b*3ab  (reduce the fraction by crossing out 2)

= 27a^{3}b^{2}  (calculate)

For 26:

A=\pi r^{2}  (equation of area of a circle)

A=\pi (3x^{3} y)^{2}  (enter the radius)

= 3\pi x^{3} y  (communtative property to reorder the terms)

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bearhunter [10]

x=1 or x=−7

Hope this helps :)

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3 years ago
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realistate agentcy commission my be based on the equation C=0.05s+500,where s repersents the total sales.if the agent sells a pr
Nataliya [291]
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3 years ago
g Suppose you are rasterizing a triangle with vertices (1, 1), (5, 1), and (2, 9), and the intensity values (e.g., redness) of t
Ivahew [28]

Answer:

6.333

Step-by-step explanation:

Our triangle vertices are

(1,1)(5,1)(2,9)

We are to perform interpolation at point(3,5)

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On vertices (5,1)(2,9)

x = 3

x1 = 5

X2 = 2

Y1 = 1

Y2 = 9

Formula for interpolation

Y = [y1+(x-x1)(y2-y1)]/x2-x

Y = 1+(3-5)(9-1)/2-5

Y = 1+[-2*8/-3]

Y = 1+16/3

From here we use use LCM to get:

19/3 = 6.333

6 0
2 years ago
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