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3 years ago

PLEASE HELP!! this is ratios

Mathematics

2 answers:

DIA [1.3K]3 years ago

6 0

Answer:

1. 8:5

2. 17;4

3. 23:6

4. I don't know

s344n2d4d5 [400]3 years ago

3 0

1. 8:5
2. 4:19
3. 6:23
4: How you find an equivalent fraction can either be dividing or multiplying by 2. 2 equivalent ratios to question 1 would be 16:10 and since we can’t divide by 5, we multiply again which would be 32:20.
(Hope this was helpful ^^)

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Which choice is equivalent to <br> 2^7 divided by 2^-3

harkovskaia [24]

Answer:

2/3 = 2×4 / 3×4 = 8/12 which is an equivalent fraction of 2/3. Similarly, if we divide the numerator and denominator of 12/18 by 6 we get. 12/18 = 12÷6 / 18÷6 = 2/3. So 12/18 is an equivalent fraction of 2/3 as well.

Step-by-step explanation:

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2 years ago

Solve the linear equation<br> 5x-10y=-5

Alexxx [7]

ANSWER WITH STEPS:

Let's solve for x.

5x−10y=−5

Step 1: Add 10y to both sides.

5x−10y+10y=−5+10y

5x=10y−5

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2 years ago

Z to the power of what equals 9?

dybincka [34]

3 to the power of 2 equals 9.

3 0

2 years ago

What is 3d − 7d + 2.8 < 5.8 − 27

weqwewe [10]

3d -7d+ 2.8 < 5.8 -27
⇒ -4d+ 2.8 < 5.8 -27
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Final answer: d > 6~

3 0

3 years ago

Solve this A tourist starts off from town A and travels for 50km on a bearing of N80°W to town B.At town B ,he continues for ano

VLD [36.1K]

Answer:

The point C is 12.68 km away from the point A on a bearing of S23.23°W.

Step-by-step explanation:

Given that AB is 50 km and BC is 40 km as shown in the figure.

From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|

=|50 sin 80° - 40 cos 20°|=11.65 km

The length of y-component of AC = |AB cos 80° - BC sin 20°|

=|50 cos 80° - 40 sin 20°|= 5 km

tan $\theta$ = 5/11.65

$\theta$ =23.23°

AC= $\sqrt{5^2+11.65^2}=12.68$ km

Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.

8 0

2 years ago