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3 years ago

Help me, please. I really need to get past this.

Mathematics

2 answers:

bazaltina [42]3 years ago

6 0

Answer:

5x=180

-5. -5.

×= 175

nekit [7.7K]3 years ago

5 0

Answer: I am pretty sure the answer is 24

Step-by-step explanation:

So since the two angles are vertical opposite angles, they are congruent angles. Then,

120 = 5x

120/5 = 5x/5

24 = x

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Ravi scores 247 points in a video game.how many more points does he need to score a total of 650?

Degger [83]

Answer:

403 points

Step-by-step explanation:

Subtract 247 from 650

4 0

3 years ago

30 pts if correct and will mark brainliest

Vladimir [108]

Answer:

{HR H O HY HG TR TO TY TG}

2600

Step-by-step explanation:

We can either get heads or tails on the coin and red yellow green or orange on the spin

HR H O HY HG

TR TO TY TG

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4 years ago

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Trigonometry problem

IgorC [24]

Answer:

The values are x = 0° or x = 60°

Step-by-step explanation:

Given:

$\cos x + \frac{1}{\sqrt{3} }\times \sin x = 1$

Let it be in the form of

$a\cos x + b\sin x = 1$ such that

a = 1

$b=\frac{1}{\sqrt{3} }$

We have

$\sqrt{(a^{2}+b^{2} )}=\sqrt{(1^{2}+(\frac{1}{\sqrt{3} }) ^{2} )}\\=\sqrt{\frac{4}{3}}\\=\frac{2}{\sqrt{3} }$

Now, Dividing both the side by $\frac{2}{\sqrt{3} }$ we get

$\frac{\sqrt{3} }{2}\cos x + \frac{1}{2}\sin x =\frac{\sqrt{3} }{2}\\$

We Know

$\sin 60 =\frac{\sqrt{3} }{2}\\and\\\cos 60 = \frac{1}{2}$

Now by replacing with above values we get

$\sin 60\times \cos x + \cos 60\times \sin x = \frac{\sqrt{3} }{2}\\$

Also we have formula

$\sin A\times \cos B + \cos A\times \sin B = \sin (A+B)$

By applying the above Formula we get

$\sin (60+x)=\frac{\sqrt{3} }{2}\\$

Also ,

$\sin (60)=\frac{\sqrt{3} }{2}\\and\\\sin (120)=\frac{\sqrt{3} }{2}$

Comparing we get

60 + x = 60 or 60 + x = 120

∴ x = 0° ∴ x = 120 - 60 = 60°

Therefore, the values are x = 0° or x = 60° i.e between 0° to 360°

5 0

3 years ago

What is the interval in which both f(x) and g(x) are positive?

padilas [110]

The positive interval of a function is when the function has positive values.

The interval in which both f(x) and g(x) are positive is $(3,\infty)$

From the given graphs of g(x), we have the following observations.

The graph of f(x) crosses the x-axis at $x =3$
The graph of g(x) also crosses the x-axis at $x =3$ .

This means that:

$(x,y)= (3,0)$ --- for both functions

But when x increases, the value of y becomes positive,

So, the positive interval of f(x) and g(x) is $(3,\infty)$

Read more about positive intervals at:

brainly.com/question/17238753

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3 years ago

Who is in NMUSD school district

Arturiano [62]

Answer:

not me

Step-by-step explanation:

not really me

why? cause i dont live there

3 0

3 years ago

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