<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
Answer: I believe it would be 42 different ways.
Step-by-step explanation:
multiply the 7 and the 6 to determine it
The answer is D
Because I worked it out
Answer:
5/24
Step-by-step explanation:
hope it works for u good luck