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Romashka-Z-Leto [24]
3 years ago
5

I want a simple explanation on how to get the answer to this question not just the answer.

Mathematics
1 answer:
AveGali [126]3 years ago
3 0
The answer is= there are 126 5p coins

the reason for this is that
-630 is simplified to 5,
-so 1/5 is really 126/630,
(630 divided by 5 is 126)
- and so 2/5 is 126 x 2 =252/630
- there are only 3 parts left, and if 1p has more parts than 5p,
-then 1p takes up 2/5 of the bag
-and 5p takes up 1/5 of the bag
You might be interested in
What is the area of the parallelogram?
Bezzdna [24]

The area of the parallelogram is mathematically given as

A = 7 square units Option B

<h3>What is the area of the parallelogram?</h3>

Generally, the equation for a parallelogram is mathematically given as

A=bH

Where

b=\sqrt{4^2+1^2}

b=4.123

and

H=1.75

Hence

A=3*1.75

A=7.2square units

In conclusion,  a parallelogram

A = 7 square units

Read more about parallelogram

brainly.com/question/1563728

#SPJ1

6 0
2 years ago
Find sinθ if cosθ = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D" id="TexFormula1" title="\frac{2}{3}" alt="\frac{2}{
stepan [7]

Answer:

sin = \frac{\sqrt{5} }{3}

Step-by-step explanation:

                                             <u>SOH CAH TOA</u>

Where:

s = sin

c = cos

t = tan

o = opposite

a = adjacent

h = hypotenuse  

cos = 2/3 where 2 is adjacent side and 3 is hypotenuse, now find opposite side using a^2 + b^2 = c^2 //c is hypotenuse side

2^2 + b^2 = 3^2

4 + b^2 = 9

b^2 = 9 - 4

b^2 = 5

b = square root (5) = 5^(1/2) //opposite side

sin = O/H

sin = \frac{\sqrt{5} }{3}

//Hope it helps.

4 0
4 years ago
The symmetry of a hyperbola with a center at (h, k) only occurs at y = k and x = h.
allsm [11]
The correct answer is false. The symmetry of a hyperbola with a center at (h, k) do not occurs only at y = k and x = h. The axis of symmetry occurs through each focus making right angles to the directrix. The axis of symmetry is a line  that divides a graph or something into two congruent figures. 
8 0
3 years ago
A storage tank will have a circular base of radius r and a height of r. The tank can be either cylindrical or hemispherical​ (ha
Neko [114]

Answer:

Volume: \frac{2}{3}\pi r^3

Ratio: \frac{2}{9}r

Step-by-step explanation:

First of all, we need to find the volume of the hemispherical tank.

The volume of a sphere is given by:

V=\frac{4}{3}\pi r^3

where

r is the radius of the sphere

V is the volume

Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:

V'=\frac{V}{2}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3

Now we want to find the ratio between the volume of the hemisphere and its surface area.

The surface area of a sphere is

A=4 \pi r^2

For a hemisphere, the area of the curved part of the surface is therefore half of this value, so 2\pi r^2. Moreover, we have to add the surface of the base, which is \pi r^2. So the total surface area of the hemispherical tank is

A'=2\pi r^2 + \pi r^2 = 3 \pi r^2

Therefore, the ratio betwen the volume and the surface area of the hemisphere is

\frac{V'}{A'}=\frac{\frac{2}{3}\pi r^3}{3\pi r^2}=\frac{2}{9}r

6 0
3 years ago
Someone answer this asap pls lots of points
DENIUS [597]

Answer:

3/4

Step-by-step explanation:

I got it right so u should tooo x

8 0
3 years ago
Read 2 more answers
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