We are given the expression
5⁹ x 5³
We can solve this using the rule of exponents which is
a^n x a^m = a^(a + m)
Therefore, the answer is
to keep the base and add the exponents
5⁵⁺³ = 5⁸<span />
Set it up as an equation: 12 + 6x = 47
(x is the reduced fee)
12 + 6x = 47
12 - 12 + 6x = 47 - 12
6x = 35
x = 35/6
x = 5.83 repeating (only the 3 is repeating)
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Required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
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Solution:
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Need to find the five terms of the sequence.
Given recursive rule is f(x) = f(x-1) -7
Substituting x = 2 , f(2) = f(2-1)-7
= f(2) = f(1) – 7 ------(1)
Also given that f(2) = 12.
On substituting the given value of f(2) in eq (1) we get
12 = f(1) – 7
f(1) = 12 + 7 = 19
Using given recursive rule and given value of f(2) calculating f(3)
Substituting x = 3 ,
f(3) = f(3-1) – 7
= f(2) – 7
= 12 – 7
= 5
Using given recursive rule and calculated value of f(3) calculating f(4)
Substituting x = 4,
f(4) = f(4-1) – 7
= f(3) – 7
= 5– 7
= -2
Using given recursive rule and calculated value of f(4) calculating f(5)
Substituting x = 5,
f(5) = f(5-1) – 7
= f(4) – 7
= -2– 7
= -9
Hence required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
Answer:
Perimeter is 14x+12
Step-by-step explanation:
The perimeter of a rectangle is P=2L+2W, therefore the perimeter is P=2(4x+7)+2(3x-1)=8x+14+6x-2=14x+12
Answer:
He made $372
Step-by-step explanation:
1692/ 36=47
47*8=372