Ask question

Ask question

All categories

3 years ago

13

A dietitian is interested in the average amount of time teenagers exercise per week. Based on previous studies, teenagers exerci

se an average of 6.5 hours per week. The dietitian suspects this average has increased. During the process of hypothesis testing, the dietitian calculates a test statistic of 3.30. If this test statistic is higher than the critical value, what can the dietitian do next

1 answer:

joja [24]3 years ago

8 0

Answer:

The dietitian should conclude that there is no significant evidence to support the claim that the number of hours teenagers exercise per week has increased.

Step-by-step explanation:

H0 : μ = 6.5

H1 : μ > 6.5

The test statistic value = 3.30

The critical value > test statistic

The Decison region :

If; test statistic > critical value (Fail to reject H0)

If; test statistic < Critical value (Reject H0)

Given that the test statistic is > critical value ; then we fail to reject the null

Hence, the dietitian should conclude that there is no significant evidence to support the claim that the number of hours teenagers exercise per week has increased.

You might be interested in

Max’s grandmother is 83 years old. Which expression should he use to find his grandmother’s age in months? (12 months = 1 year)

NISA [10]

Answer:

83x12

Step-by-step explanation:

5 0

3 years ago

U={1,2,3,4,5,6,7,8,9} <br> a={2,4,6,8} <br> b={3,6,9} <br><br> What is the set AUB?

ella [17]

Answer:

AUB = {2,3,4,6,8,9}

Step-by-step explanation:

The set u should not be included in set AUB

5 0

3 years ago

Choose the correct answer. > < = We can't compare them= fastbridge quiz amath

Verizon [17]

Answer:

$\leq$ or $\geq$

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help this is due today please i really need help it’s due in 4 hours!!!

Anarel [89]

Answer:

y=36 and X=44

Step-by-step explanation:

7 0

2 years ago

Please help me <br> Show your work <br> 10 points

Svet_ta [14]

<h2>Answer</h2>

After the dilation $\frac{5}{3}$ around the center of dilation (2, -2), our triangle will have coordinates:

$R'=(2,3)$

$S'=(2,-2)$

$T'=(-3,-2)$

<h2>Explanation</h2>

First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:

$(x,y)$ → $(x-2, y+2)$

Next, we are going to perform our dilation, so we are going to multiply our resulting point by the dilation factor $\frac{5}{3}$ . Therefore our second partial rule will be:

$(x,y)$ → $\frac{5}{3} (x-2,y+2)$

$(x,y)$ → $(\frac{5}{3} x-\frac{10}{3} ,\frac{5}{3} y+\frac{10}{3} )$

Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)

$(x,y)$ → $(\frac{5}{3} x-\frac{10}{3}+2,\frac{5}{3} y+\frac{10}{3}-2)$

$(x,y)$ → $(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})$

Now that we have our rule, we just need to apply it to each point of our triangle to perform the required dilation:

$R=(2,1)$

$R'=(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})$

$R'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(1)+ \frac{4}{3})$

$R'=(\frac{10}{3} -\frac{4}{3} ,\frac{5}{3}+ \frac{4}{3})$

$R'=(2,3)$

$S=(2,-2)$

$S'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})$

$S'=(\frac{10}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})$

$S'=(2,-2)$

$T=(-1,-2)$

$T'=(\frac{5}{3} (-1)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})$

$T'=(-\frac{5}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})$

$T'=(-3,-2)$

Now we can finally draw our triangle:

8 0

3 years ago