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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! Factor x^2 + 25 in the complex numbers.

Mathematics

1 answer:

oksian1 [2.3K]3 years ago

7 0

Answer: C) (x + 5i)(x - 5i)

Step-by-step explanation:

x² + 25 can be rewritten as x² - (-25)

Now use the difference of squares to factor: a² - b² = (a + b)(a - b)

√x² = x √-25 = 5i

--> x² + 25 = (x + 5i)(x - 5i)

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Solve x2 – 8x + 15 < 0. Select the critical points for the inequality shown.

quester [9]

Answer:

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Explanation:

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(x2−2⋅x⋅4+42)+15=16

or,(x−4)2+15−16=0

or,(x−4)2−1=0

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This is the a2−b2=(a+b)(a−b)form.

(x−4+1)(x−4−1)=0

or,(x−3)(x−5)=0

Now, equate both the terms to zero since both of them when multiplied, give zero.

Either,

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Or,

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Ans:x=3,5 Hope this helpsXD...!!

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3 years ago

Read 2 more answers

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3 years ago

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4 years ago

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4 years ago

What is the solution for the following equation? x^2-6x+9=11

tankabanditka [31]

Make one side equal zero
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3 years ago