Answer:
2 x y^2 (x y - 1) (x y - 3)
Step-by-step explanation:
2x^3y^4-8x^2y^3+6xy^2
each term contains 2xy^2 so factor that out
2xy^2(x^2y^2 -4xy+3)
then lets factor the inside
what terms multiply together to give us +3 and add to -4
-3* -1 = 3 -3+-1 =-4
2 x y^2 (x y - 1) (x y - 3)
The first term of the sequence is -3.
According to the formula each next term will be obtained by multiplying the previous term by 2.
So, next terms will be:
Second term = 2 x First Term = 2 x (-3) = - 6
Third term = 2 x (-6) = -12
Fourth term = -24
Fifth term = -48
Sixth term = -96
So, the sequence will be:
-3, -6, -12, -24, -48, -96 ...
(3+a+2) (a+2-3)
(5+a) (a-1)
5a-5+a^2-a
Rearrange and combine like terms
a^2 +4a-5
The values -3, -9 and -12 satisfy the inequality.
In this question we evaluate each element of the set to determine whether value belongs to the inequation given on statement:
x = 0
(FALSE)
x= -3
(TRUE)
x = -9
(TRUE)
x = -12
(TRUE)
The values -3, -9 and -12 satisfy the inequality.
We kindly invite to see this question on inequalities: brainly.com/question/17675534
