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Natasha_Volkova [10]
3 years ago
15

9,-81, 729,-6561... What is the common ratio? Help which is the correct answer?

Mathematics
1 answer:
GrogVix [38]3 years ago
7 0

Answer:

r = -9

Step-by-step explanation:

Given

Sequence: 9,-81, 729,-6561...

Required

Determine the common ratio

The common ratio r is calculated using:

r = \frac{T_n}{T_{n-1}}

Let n = 2

So, we have:

r = \frac{T_2}{T_{2-1}}

r = \frac{T_2}{T_1}

From the sequence:

T_2 = -81

T_1=9

So, the equation becomes

r = \frac{-81}{9}

r = -9

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The volume of a gas varies directly with its temperature and inversely with the pressure. If the volume of a certain gas is 15 c
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Answer:

Therefore the volume of the gas is 32 cubic feet.

Step-by-step explanation:

Given that,

The volume of a gas varies directly with its temperature and inversely with the pressure.

V\propto \frac{T}{P}

V= Volume of the gas at constant mass

T= Temperature at constant mass

P= pressure at constant mass

\frac{V_1}{V_2}=\frac{\frac{T_1}{T_2}}{\frac{P_1}{P_2}}

\therefore \frac{V_1}{V_2}=\frac{T_1P_2}{T_2P_1}.

Given that,

At constant mass, the volume of a certain gas is 15 cubic feet and a pressure of 40 pound per square inch at a temperature 300 k.

V_1=15 cubic feet, P_1=40 pound per square inch and T_1= 300 K

V_2=?, P_2=20 pound per square inch and T_2= 320k

\therefore \frac{V_1}{V_2}=\frac{T_1P_2}{T_2P_1}.

Plugging all values

\frac{15}{V_2}=\frac{300\times 20}{320\times 40}

\Rightarrow V_2=\frac{15\times 320\times 40}{300\times 20}{}

\Rightarrow V_2=32 cubic feet

Therefore the volume of the gas is 32 cubic feet.

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