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3 years ago

Wich figure is a translation of figure 1

Mathematics

1 answer:

balu736 [363]3 years ago

3 0

Answer:

figure 5

Step-by-step explanation:

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Which of the following are solutions to the equation below?

Over [174]

B and E are correct.

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2 years ago

Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2

exis [7]

The Jacobian for this transformation is

$J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}$

with determinant $|J| = 12$ , hence the area element becomes

$dA = dx\,dy = 12 \, du\,dv$

Then the integral becomes

$\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv$

where $R'$ is the unit circle,

$\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1$

so that

$\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv$

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

$\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}$

Then

$\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}$

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2 years ago

Can someone answer my previous question pleaseeee

Georgia [21]

Answer:

all done bud, I'm just here for the extra points :D

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3 years ago

Read 2 more answers

What is this? (2 photos please look and just answer A, B, or C)

igomit [66]

I think the answer is C

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2 years ago

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What is the unit rate of y = 2/3x ? ( must satisfy the definition of unit rate )

Nat2105 [25]

The unit rate is 2/3 because in the line y=2/3x, 2/3 is the slope (y=mx+b). The slope of the line is pretty much the definition of a unit rate because the unit rate is a constant addition or subtraction over and over. In addition, it is a straight line(y=mx+b) and the values are going up at a constant rate of 2/3.

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3 years ago