In a right triangle, sin(40 - 2) = cos(32)'. What is the value of x?

Mathematics

1 answer:

o-na [289]2 years ago

5 0

Answer:

x = 25

Step-by-step explanation:

Correct question

In a right triangle Sin (40-x)=cos(3x) what is the value of x

Since Sin theta = Cos(90-theta)

Sin (40-x) = Sin(90-3x)

40 - x = 90 - 3x

-x+3x = 90 - 40

2x = 50

x = 25

Hence the value of x is 25

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<h3>What is quadratic equation?</h3>

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Given:

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