I NEED HELP!!

H(x)=3x-1; Find h(-5)

Taya2010 [7]

Answer:

I'm not sure but I got -16

Step-by-step explanation:

I just plugged in the -5 in place for the x

5 0

4 years ago

59. If <img src="https://tex.z-dn.net/?f=%5Clim%20_%7Bx%20%5Crightarrow%201%7D%20%5Cfrac%7Bf%28x%29-8%7D%7Bx-1%7D%3D10%2C" id="T

denpristay [2]

Answer:

$\large\lim_{x\rightarrow 1} f\left( x\right)=8$

Step-by-step explanation:

$\lim_{x\rightarrow 1} \frac{f\left( x\right) -8}{x-1} =10$

$\lim_{x\rightarrow 1} f\left( x\right) -8=10\times \lim_{x\rightarrow 1}\left( x-1\right)$

$\lim_{x\rightarrow 1} f\left( x\right) -8=10\times\left( (1)-1\right)$

$\lim_{x\rightarrow 1} f\left( x\right) -8=10\times\left( 0\right)=0$

$\lim_{x\rightarrow 1} f\left( x\right) -8=0$

$\lim_{x\rightarrow 1} f\left( x\right) =8$

7 0

3 years ago

X+3y=37 Can someone help please

Anvisha [2.4K]

Answer:

there are two ways we can solve this problem the first way is in x-form and the second way is in y-form I will give you the answer for each of the ways.

Step-by-step explanation:

x-form: x=37-3y

y-form: y=37/3 - x/3

hope this helps if this was not the way you wanted me to solve it please let me know and I will do it the way you want me to do it.

7 0

3 years ago

Read 2 more answers

Which operation results in an expression equivalent to ? 23y^4 - 6y^3 + 35y^2 - 20y

Tom [10]

Answer:

D. P + Q

Explanation:

Given:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7)

Required:

Determine which operation will give an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

SOLUTION:

Perform each operation given to see which of them gives an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

Q - P:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7)

Q - P = (5y² - 4y)(3y² + 7) - (8y⁴ + 6y³ + 8y)

(5y²(3y² + 7) -4y(3y² + 7)) - (8y⁴ + 6y³ + 8y)

(15y⁴ + 35y² - 12y³ - 28y) - (8y⁴ + 6y³ + 8y)

Open parentheses

15y⁴ + 35y² - 12y³ - 28y - 8y⁴ - 6y³ - 8y

Collect like terms

15y⁴ - 8y⁴ - 12y³ - 6y³ + 35y² - 28y - 8y

7y⁴ - 18y³ + 35y² - 36y

Therefore, P - Q does not give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

PQ:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

PQ = (8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y)

=(8y⁴(15y⁴ + 35y² - 12y³ - 28y) +6y³(8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y) +8y(8y⁴ + 6y³ + 8y)(15y⁴ + 35y² - 12y³ - 28y))

= 120y⁸ . . . . .

Note: You don't need to perform this operation further anymore. It would definitely not give us the equivalent expression we are looking for. The degree of the leading term (120y⁸) is way too greater than the degree of the leading term (23y⁴) of the equivalent expression we are looking for.

Thus, PQ cannot give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

P - Q:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

P - Q = (8y⁴ + 6y³ + 8y) - (15y⁴ + 35y² - 12y³ - 28y)

Open parentheses

8y⁴ + 6y³ + 8y - 15y⁴ - 35y² + 12y³ + 28y

Collect like terms

8y⁴ - 15y⁴ + 6y³ + 12y³ - 35y² + 8y + 28y

-7y⁴ + 18y³ - 35y² + 36y

Therefore, P - Q cannot give us an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

P + Q:

P = 8y⁴ + 6y³ + 8y

Q = (5y² - 4y)(3y² + 7) = (15y⁴ + 35y² - 12y³ - 28y)

P + Q = (8y⁴ + 6y³ + 8y) + (15y⁴ + 35y² - 12y³ - 28y)

Open parentheses

8y⁴ + 6y³ + 8y + 15y⁴ + 35y² - 12y³ - 28y

Collect like terms

8y⁴ + 15y⁴ + 6y³ - 12y³ + 35y² + 8y - 28y

23y³ - 6y³ + 35y² - 20y

Therefore, P + Q will result in an expression equivalent to 23y⁴ - 6y³ + 35y² - 20y.

The answer is D.

7 0

3 years ago

W W 1000 A) 35° C) 25° B) 55° D) 40°

Vlad [161]

Answer:

I don't get the question well,so if u can reframe it

8 0

3 years ago