Answer:
E
Step-by-step explanation:
dy/dx - sqrt(x/y) = 0
dy/dx = sqrt(x) ÷ sqrt(y)
y^½ .dy = x^½ .dx
Add 1 to the power and divide by the new power
(⅔)y^(3/2) = (⅔)x^(3/2) + c
x = 1, y = 0
0 = ⅔ + c
c = ⅔
(⅔)y^(3/2) = (⅔)x^(3/2) + ⅔
y^(3/2) = x^(3/2) + 1
At y = 73
73^(3/2) = x^(3/2) + 1
622.7122734 = x^(3/2)
x = 622.7122734^⅔
x = 72.9219527
Approximately 73
Answer:
you would have 8 cents
Step-by-step explanation:
:D hope this helps!!
If the number of samples is increased, this actually leads
to a reduction in error of the distribution. This is because of the
relationship between variation and sample size which has the formula of:
σx = σ / sqrt (n)
So from the formula we can actually see that the variation
and sample size is inversely proportional.
Which means that increasing the sample size results in a
reduction of variation.
Answer:
It will have less variation
Answer:
sorry I didn't have my phone on me, look at the photo it's the answer btw
Step-by-step explanation:
- 
+ 6
divide each term on the numerator by 7b
= - 7
/ 7b + 42 / 7b
= - + 6
