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enyata [817]
3 years ago
15

In quadrilateral ABDC, AB ∥ CD. Which additional piece of information is needed to determine that ABDC is a parallelogram?  i ne

ed help asap

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
5 0

ac would have to be equivalent to bd so your answer would be: the additional piece of information needed is ac=bd


tatiyna3 years ago
4 0

Answer:  The answer is AB = CD.

Step-by-step explanation: We are given a quadrilateral ABCD with AB ║ CD.

We know that a quadrilateral is said to be a parallelogram if any one of the following conditions is satisfied:

(i)  If both pairs of opposite angles of a quadrilateral are equal, then it is a parallelogram.

(ii) If one pair of opposite sides of a quadrilateral is both equal and parallel, then it is a parallelogram.

(iii) If the diagonals of a quadrilateral bisect each other, then it is a parallelogram.

We are given that AB is parallel to CD, so by the condition (ii), if we get the additional information that AB = CD, then ABCD will be a parallelogram.

Thus, the answer is AB = CD.

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Solve, be sure to show each step under the original problem for any credit.<br> 1 =k/12 +5
Naya [18.7K]
K = -48

1. subtract 5 from both sides
-4 = k/12

2. multiply 12 from both sides to get k alone
-48 = k


3 0
3 years ago
Please answer quickly
scZoUnD [109]

f(x)=(x+a)/b

or bf(x)=x+a

let f(x)=y

by=x+a

flip x and y

bx=y+a

or y=bx-a

or f^{-1}(x)=bx-a

also g(x) is inverse of f(x)

bx-a=cx-d

so b=c,a=d

again let g(x)=y

y=cx-d

flip x and y

x=cy-d

cy=x+d

y=(x+d)/c

or g^{-1}(x)=(x+d)/c

also f(x) is inverse of g(x)

so (x+a)/b=(x+d)/c

so a=d,b=c

so in either case a=d,b=c

take b=c=1

a=d=2

f(x)=(x+2)/1=x+2

g(x)=1x-2=x-2

so f(x) and g(x) are two parallel lines f(x) with y- intercept=1 and slope 0

g(x) with y-intercept -2 and slope 0

if we take b=c=2,a=d=3

f(x)=(x+3)/2=x/2+3/2

g(x)=2x-3

here f(x) is of slope 1/2 and y-intercept 3/2

g(x) is of slope 2 and y intercept -3

part 3.

f(f(x))=g((x+a)/b)=c[(x+a)/b]-d=(c/b)(x+a)-d

5 0
2 years ago
Which expression is equivalent to StartRoot 120 x EndRoot?.
Irina-Kira [14]

Here for 120, the expression for the start root and end root is given  

\sqrt{120} =2\sqrt{30}

<h3>What will be the expression for start root and enroot of 120?</h3>

Here we need to find \sqrt{120}

By simplifying the given expression, we get:

120=2\times2\times2\times3\times5

120=(2^{2} )\times3\times5

by taking square roots on both sides we get

\sqrt{120} =2\sqrt{30}

Thus for 120, the expression for the start root and end root is given  \sqrt{120} =2\sqrt{30}

To know more about the Square roots follow

brainly.com/question/124481

5 0
2 years ago
Carlos takes classes at both Westside Community College and Pinewood Community College. At Westside, class fees are $ 98 per cre
Sholpan [36]

Answer:

x + y = 13

98x + 115y = z

Step-by-step explanation:

Let x represent the time spent taking class in Westside community college

Let y represent the time spent taking class in Pinewood community college

Let z represent the combined total amount paid for the class fees.

The total combined time for the two school is given as:

x + y = 13.

For the combined total amount; we multiply the price for each school with the time spent on the school and sum them together.

Westside: 98 * x = 98x

Pinewood: 115 * y = 115y

The combined total amount represented as z is given as:

z = 98x + 115y

7 0
3 years ago
The odds that you will pick a heart from a standard deck of 52 cards is 13:39.
podryga [215]
Not exactly sure but I think it's false hope this helps
3 0
3 years ago
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