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vladimir1956 [14]
3 years ago
12

Write equations for the vertical and horizontal lines passing through the point (-8, -3).

Mathematics
1 answer:
tangare [24]3 years ago
7 0

Answer:

x=-8

y=-3

Step-by-step explanation:

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Which expression shows that the quotient
Harrizon [31]

Answer:

Option (2)

Step-by-step explanation:

Given expression is \frac{2}{(3x-1)} ÷ \frac{6}{6x-1}

We further simplify this expression,

\frac{2}{(3x-1)} ÷ \frac{6}{6x-1}

= \frac{2}{(3x-1)}\times \frac{6x-1}{6}

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= \frac{6x-1}{(9x-3)}

Therefore, \frac{6x-1}{(9x-3)} will be the quotient of the given expression.

x\neq \frac{1}{3} and x\neq \frac{1}{6} for which the given expression is not defined.

Option (2) will be the answer.

6 0
3 years ago
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nalin [4]

(y+20)=1(x+10); First, we can find the slope by using the equation y2-y1/x2-x1.

-9+20/1+10 (Accounting for double negatives).

11/11 = 1

The slope of the equation is 1, now we just need to pick a set of points from which we derived the slope from (doesn't matter which) as y1 and x1 in the point-slope equation. (y-y1)=m(x-x1)

Your final answer can either be (y+20)=1(x+10) or (y+9)=1(x-1) but in the context of this question it is (y+20)=1(x+10)

8 0
3 years ago
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