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Angelina_Jolie [31]
3 years ago
7

Evaluate 2-(-4)+(-y) where y = 7

Mathematics
2 answers:
Levart [38]3 years ago
7 0
2+4=6
6+-7=-1
Your answer would be negative 1 or -1
joja [24]3 years ago
5 0

Answer:

-1

Step-by-step explanation:

It’s just simple don’t worry just look I won’t make you need the explanation god bless :)

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12 and 1/2<u>
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Step-by-step explanation:

8 0
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Can someone help me wit #4 plzz
iris [78.8K]

Answer: It represents the area of the two circular sides ("lids")

Explanation:

Imagine you made a cylinder out of 3 pieces of paper. The cylinder can be decomposed into two circular shapes (radius r) and one rectangular piece with two side lengths: one is "h", the other has to be long enough to go around each of the disks, so it has to be 2*pi*r long.

So the term 2*pi*r*h is the area of the rectangular piece and pi*r^2 is the area of each of the "lids" Since there are two of those, the term 2*pi*r^2 represents the area of the bottom and top lids.

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An educational researcher is studying two similar high schools in different states. Suppose that 50% of all
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The answer is 525, meaning it’s more than it should be, hope i helped!
4 0
3 years ago
work for a publishing company. The company wants to send two employees to a statistics conference. To be​ fair, the company deci
Yuki888 [10]

Answer:

(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}

(b) The probability that Roberto and John attend the​ conference is 0.10.

(c) The probability that Clarice attends the​ conference is 0.40.

(d) The probability that John stays​ home is 0.60.

Step-by-step explanation:

It is provided that :

Marco (<em>M</em>), Roberto (<em>R</em>), John (<em>J</em>), Dominique (<em>D</em>) and Clarice (<em>C</em>) works for the company.

The company selects two employees randomly to attend a statistics conference.

(a)

There are 5 employees from which the company has to select two employees to send to the conference.

So the total number of ways to select two employees is:

{5\choose 2}=\frac{5!}{2!(5-2)!}=\frac{5\times 4\times 3!}{2\times 3!}=10

The 10 possible samples are:

MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC

(b)

The probability of the event <em>E</em> is:

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = Total number of outcomes.

The variable representing the selection of  Roberto and John is, <em>RJ</em>.

The favorable number of outcomes to select Roberto and John is, 1.

The total number of outcomes to select 2 employees is 10.

Compute the probability that Roberto and John attend the​ conference as follows:

P(RJ)=\frac{n(RJ)}{N}=\frac{1}{10}=0.10

Thus, the probability that Roberto and John attend the​ conference is 0.10.

(c)

The favorable outcomes of the event where Clarice attends the conference are:

n (C) = {MC, RC, JC and DC} = 4

Compute the probability that Clarice attends the​ conference as follows:

P(C)=\frac{n(C)}{N}=\frac{4}{10}=0.40

Thus, the probability that Clarice attends the​ conference is 0.40.

(d)

The favorable outcomes of the event where John does not attends the conference are:

n (J') = MR, MD, MC, RD, RC, DC

Compute the probability that John stays​ home as follows:

P(J')=\frac{n(J')}{N}=\frac{6}{10}=0.60

Thus, the probability that John stays​ home is 0.60.

4 0
3 years ago
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enyata [817]
Alright so basically what you have to do here is realize that 130 miles is 2 hours, so if you divide by 2, you’ll have 65 miles in one hour ,, so 6mph, and if you divide again by two, you have 32.5 miles ,, therefore he travels 32.5 miles in 30 minutes
4 0
3 years ago
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