48.012001 is the answer to this problem
Lets say for arguments sake that the bag contained 2 blue and 3 red marbles
p:q = 2:3 In order to get a ratio of 2:1 we would have to add 4 blue marbles
(6:3 = 2:1).
So the ratio p to r = 2:4 = 1:2 answer.
7.66. If 100%=1, then 700%= 7. Then if 10%=.1 then 60%=.6. And lastly if 1%=.01 then 6%=.06. Add them all up: 7+.6+.06= 7.66. HTH
Step-by-step explanation:
12,500.
Step-by-step explanation:
We have been given that a salesperson works 40 hours per week at a job where he has two options for being paid. Option A is an hourly wage of $25. Option B is a commission rate of 8% on weekly sales.
First of all we will find amount earned by salesperson with option A.
\text{Option A earnings}=40\times 25=1000Option A earnings=40×25=1000
The salespersons earns $1000 through option A.
Let x be the amount of weekly sales.
8% of x should be equal to 1000 for salesman to earn the same amount with the two options.
\frac{8}{100}x=1000
100
8
x=1000
0.08 x=10000.08x=1000
x=\frac{1000}{0.08}x=
0.08
1000
x=12500x=12500
Therefore, the salesman needs to make a weekly sales of $12,500 to earn the same amount with two options.
Answer:
Step-by-step explanation:
The Universal Set, n(U)=2092
Let the number who take all three subjects, 
Note that in the Venn Diagram, we have subtracted from each of the intersection of two sets.
The next step is to determine the number of students who study only each of the courses.
![n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x](https://tex.z-dn.net/?f=n%28S%5C%3Aonly%29%3D1232-%5B103-x%2Bx%2B23-x%5D%3D1106%2Bx%5C%5Cn%28F%5C%3A%20only%29%3D879-%5B103-x%2Bx%2B14-x%5D%3D762%2Bx%5C%5Cn%28R%5C%3Aonly%29%3D114-%5B23-x%2Bx%2B14-x%5D%3D77%2Bx)
These values are substituted in the second Venn diagram
Adding up all the values
2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]
2092=2085+x
x=2092-2085
x=7
The number of students who have taken courses in all three subjects,
