The expression into a single logarithm is ![log[(x)^{10}][(2)^{30}]](https://tex.z-dn.net/?f=log%5B%28x%29%5E%7B10%7D%5D%5B%282%29%5E%7B30%7D%5D)
Step-by-step explanation:
Let us revise some logarithmic rules
∵ 10 log(x) + 5 log(64)
- At first re-write 10 log(x)
∴ 10 log(x) = 
- Then re-write 5 log(64)
∴ 5 log(64) = 
∴ 10 log(x) + 5 log(64) = +
- Use the 3rd rule above to make it single logarithm
∵ + = ![log[(x)^{10}][(64)^{5}]](https://tex.z-dn.net/?f=log%5B%28x%29%5E%7B10%7D%5D%5B%2864%29%5E%7B5%7D%5D)
∴ 10 log(x) + 5 log(64) =
∵ 64 = 2 × 2 × 2 × 2 × 2 × 2
∴ We can write 64 as 
∴ 
- Multiply the two powers of 2
∴ 
∴ 10 log(x) + 5 log(64) =
The expression into a single logarithm is
Learn more:
You can learn more about the logarithmic functions in brainly.com/question/11921476
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The answer is D (y=-2x+1)
Answer:
the answer is area of field =width ×length
Step-by-step explanation:
=w×40
=40w
hence 40 w =area
#1: 214 tickets split 9 ways does not work out to an integer number. Nobody wants 2/3 of a ticket, right?
So the trick here is to determine the first multiple of 9 greater than 214.
Note that 214/9 = 23.8. No good. Not an integer.
Multiply 23 by 9; we get 207. Multiply 24 by 9; we get 216.
So, given that we have 214 tickets already, we need 2 more, to make 216.
Check: Is 216 divisible by 9 without a remainder? Yes. Then each of the 9 students will get 24 tickets.
The rest of the problems are somewhat similar to this one.
See whether you can do the next one, #2.
If you'd share your results, I'd be happy to comment on what you've done.
16 x 5= 80. 80 divided by 2 (50 percent) is 40.
