It is 1a over bd and 8 over k
Answer:
dh/dt = 3/25π m/min
Step-by-step explanation:
Radius = 5m
Rate (dV/dt) = 3 cm^3 / min
Leaking rate = 1 cm^3 / min
Volume = πr^2h
Volume = π(5)^2h
V= 25πh
Differentiate volume implicitly with respect to time
dV/dt = 3 cm^3/min
3 = 25π(dh/dt)
dh/dt = 3 m^3/min /25πm^2
dh/dt = 3/25πm/min
Answer: Non- Statistical
Step-by-step explanation:
It just isn't
I think this is √2n-5 = 10.
