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scoundrel [369]
3 years ago
11

HELP !!!!!!!!!!! find l

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer:

Pythagorean Theorem: a^2 + b^2 = c^2

6^2 + 15^2 = c^2

36 + 225 = 261

So, the answer is 261

Let me know if this helps!

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If $x$, $y$, and $z$ are positive integers such that $6xyz+30xy+21xz+2yz+105x+10y+7z=812$, find $x+y+z$.
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Step-by-step explanation:

When we simplify we get $$z(6xy+21x+2y+7)+30xy+105x+10y=812.$$

Then we continue to factor to get: (z+5)(6xy+21x+2y+7)&=847.

We then see that we can factor (6xy+21x+2y+7) into (z+5)(3x+1)(2y+7)&=847.

we then do the prime factorization of 847, which i think is,  7*11*11. we have to find the numbers that multiply to 847 and then plug them into z+5, 3x=1,2y+7.

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We also see that 3x+1=11 so we see that x=10/3 (which wont work).

So 3x+1=7, so x=2.

So 11 has to be in another term. It has to be in 2y+7=11 so y=2

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8 0
4 years ago
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3 years ago
Factoring with two variables 6w^4-54w^2
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4 0
3 years ago
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