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HACTEHA [7]
3 years ago
8

A. Write the given equation in standard form.8x+3y+6=0

Mathematics
1 answer:
Vikki [24]3 years ago
4 0

Answer:

8x+3y=-6

Step-by-step explanation:

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Convert each unit of length​
lina2011 [118]
6cm= 600 cm
48,000mm= 48m
5 0
3 years ago
The quantity p varies inversely as the square of (q + 2) <br>p=5 when q = 3 <br>Find p when q = 8​
MArishka [77]

Answer:

p = 1.25

Step-by-step explanation:

varies inversely

p (q + 2)² = k

-----------------------

Find k

p=5 when q = 3

5(3 + 2)² = k

5(25) = k

125 = k

----------------------

Find p when q = 8​

p(8 + 2)² = 125

p(100) = 125

divide both sides by 100

p = 1.25

7 0
3 years ago
What is the pattern of 1, 3, 7, 13, 21
Talja [164]
+2 +4 +6 +8 basically multiples of 2 or even numbers
3 0
4 years ago
Which statement correctly describe the data shown in the scatter plot?
pentagon [3]

Answer:

Option C is correct, The scatter plot shows a positive association because y increases as x increases.

Step-by-step explanation:

We are given a graph of scatter plot of points. We need to choose correct option using graph.

Option A: The point (18,2) is an outlier. This point is not shown on graph.

False.

Option B: The scatter plot show linear association. This is not linear association because points are not col-linear.

False

Option C: The scatter plot shows a positive association. This is positive association because y increases as x increases.

True

Option D: The scatter plot shows no association. This is false because it shows positive association.

False

7 0
3 years ago
Read 2 more answers
A local board of education conducted a survey of residents in the community concerning a property tax levy on the coming local b
IrinaK [193]

Answer:

a. [ 0.454,0.51]

b. 599.472 ~ 600

Step-by-step explanation:

a)

Confidence Interval For Proportion

CI = p ± Z a/2 Sqrt(p*(1-p)/n)))

x = Mean

n = Sample Size

a = 1 - (Confidence Level/100)

Za/2 = Z-table value

CI = Confidence Interval

Mean(x)=410

Sample Size(n)=850

Sample proportion = x/n =0.482

Confidence Interval = [ 0.482 ±Z a/2 ( Sqrt ( 0.482*0.518) /850)]

= [ 0.482 - 1.645* Sqrt(0) , 0.482 + 1.65* Sqrt(0) ]

= [ 0.454,0.51]

b)

Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)

Z a/2 at 0.05 is = 1.96

Samle Proportion = 0.482

ME = 0.04

n = ( 1.96 / 0.04 )^2 * 0.482*0.518

= 599.472 ~ 600

8 0
3 years ago
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