All categories

2 years ago

May someone please help?

Mathematics

2 answers:

Ronch [10]2 years ago

8 0

(-7,3) here is the answer, easy one

pashok25 [27]2 years ago

5 0

Answer:

B' = (-7,3)

Step-by-step explanation:

B = (7,3)

mirrored would be:

B' x position would be -7

B' y position would not change

B' = (-7,3)

You might be interested in

A computer system password requires five characters, all lowercase letters (remember there are 26 letters), and all the letters

Goshia [24]

26 divided by 5 = 5.2

3 0

2 years ago

Please help me figure this out

grin007 [14]

I believe the answer is B

6 0

3 years ago

Read 2 more answers

The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width

blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given perimeter

perimeter of rectangle = 2 ( length + width )

=> 30.8 km = 2 ( x + y )

=> $x + y = \frac{30.8}{2}$

=> y = 15.4 – x ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,

=> $length^2 + width^2 = diagonal^2$

=> $x^2 + y^2 = 11^2$

=> $x^2 + y^2 = 121$

On substituting value of y from (1) in above equation we get

=> $x^2 + (15.4-x)^2 = 121$

=> $x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x = 121$

=> $2x^2-30.8x + 237.16 -121 = 0$

=> $2x^2-30.8x + 116.16 = 0$

Solving above quadratic equation using quadratic formula

General form of quadratic equation is

$ax^2 +bx +c = 0$

And quadratic formula for getting roots of quadratic equation is

$x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}$

As equation is $2x^2-30.8x + 116.16 = 0$ , in our case

a = 2 , b = -30.8 and c = 116.16

Calculating roots of the equation we get

$x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}$

$x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}$

$x=\frac{30.8\pm\sqrt{860.64}}{4}$

$x=\frac{(30.8\pm29.33)}4$

$x=\frac{(30.8+29.33)}{4}$

$x=\frac{(30.8-29.33)}{4}$

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0

3 years ago

Last Monday local mail carriers delivered 1,344 pieces of mail. Of all the deliveries they made, 1 / 6 were magazines, 1 / 12 we

Brut [27]

Answer: 1008 letters

Step-by-step explanation:

From the question, last Monday, a local mail carriers delivered 1,344 pieces of mail and of all the deliveries they made, 1 / 6 were magazines, 1 / 12 were packages, and the rest were letters. The fraction of letters will be:

= 1 - (1/6 + 1/12)

= 1 - (3/12)

= 9/12 = 3/4

We will now multiply 3/4 by 1344 to get the number of letters delivered.

= 3/4 × 1344

= 1008 letters

6 0

2 years ago

Can a remainder in a division problem equal the divisor

Rufina [12.5K]

Well the answer is No.A remainder will always be smaller than the divisor ,because the divisor is the one that used to divide the dividend and the remaining number that cannot be divided by the divisor is called the remainder.
Questions?

6 0

2 years ago