Answer:
Question 2: The degree is 3 and the terms are 2, Binomial
Question 3: The degree is 2 and the terms are 3, Polynomial
Step-by-step explanation:
Answer:
0.3 to 2.3 min
Step-by-step explanation:
n1=n2=10
x1=48
x2=49
s1=4
s2=1
Determine the deegres of freedom.

t=2.037 (student's appendix)



We are 95% confident that average commuting time for rute A is between 0.3 and 2.3 min shorter than for rute B.
the general equation for velocity in terms of acceleration and displacement is: v² = v₀² + 2ax.
Solve for a: a = (v² - v₀²)/(2x).
You are given v₀ and v, and x is easy to calculate since you are given its initial and final values. The rest is just arithmetic.
(note also: SI expressions have a required space between the coefficient and the unit symbol. Thus you should have things such as “15 m” and “-2 m·sˉ¹” instead of “15m” and “-2m·sˉ¹”.)
vi is going in the positive direction (up). (That's my choice). a (acceleration) is going in the minus direction (down). The directions could be reversed.
Givens
vi = 160 ft/s
vf = 0 (the rocket stops at the maximum height.)
a = - 9.81 m/s
t = ????
Remark
YOu have 4 parameters between the givens and what you want to solve. Only 1 equation will relate those 4. Always always list your givens with these problems so you can pick the right equation.
Equation
a = (vf - vi)/t
Solve
- 32 = (0 - 160)/t Multiply both sides by t
-32 * t = - 160 Divide by -32
t = - 160/-32
t = 5
You will also need to solve for the height to answer part B
t = 5
vi = 160 m/s
a = - 32
d = ???
d = vi*t + 1/2 a t^2
d = 160*5 + 1/2 * - 32 * 5^2
d = 800 - 400
d = 400 feet
Part B
You are at the maximum height. vi is 0 this time because you are starting to descend.
vi = 0
a = 32 m/s^2
d = 400 feet
t = ??
formula
d = vi*t + 1/2 a t^2
400 = 0 + 1/2 * 32 * t^2
400 = 16 * t^2
400/16 = t^2
t^2 = 25
t = 5 sec
The free fall takes the same amount of time to come down as it did to go up. Sort of an amazing result.
Answer:

Step-by-step explanation:
x² + 5x + 3 = 0
x = (- 5 +/- √5² - 4x1x3)/2x1
= (-5+/-√13)/2
x₁ = (- 5 + √13)/2
x² = (- 5 - √13)/2