Y1 is the simplest parabola. Its vertex is at (0,0) and it passes thru (2,4). This is enough info to conclude that y1 = x^2.
y4, the lower red graph, is a bit more of a challenge. We can easily identify its vertex, which is (-4,0), and several points on the grah, such as (2,-3).
Let's try this: assume that the general equation for a parabola is
y-k = a(x-h)^2, where (h,k) is the vertex. Subst. the known values,
-3-(-4) = a(2-0)^2. Then 1 = a(2)^2, or 1 = 4a, or a = 1/4.
The equation of parabola y4 is y+4 = (1/4)x^2
Or you could elim. the fraction and write the eqn as 4y+16=x^2, or
4y = x^2-16, or y = (1/4)x - 4. Take your pick! Hope this helps you find "a" for the other parabolas.
Answer:
I'm pretty sure its B.
Step-by-step explanation:
lame couldn't just answer smh
83 ft per minute an that is how I got my awnser
Answer:
Thus, in total, there are 24=16 ways to answer the four questions. Only one of these 16 sequences is correct. Assuming each of these 16 sequences is equally likely to occur (as would result from random guessing), the probability that all four questions are answered correctly is 1/16.
4 times 1 equals 4 then do 81 minus 4 which equals 77 so 77 is your answer
