Peter attempted to use the divide-center method to find the line of best fit on a scatterplot.
1 answer:
Answer:
He had a different number of points above the line of best fit than below the line of best fit.
Step-by-step explanation:
This is the best likely answer to the question about Peter's attempt to use divide-center method to find the line of best fit on a scatterplot.
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Answer:542.5
Step-by-step explanation:

<u>Step-by-step explanation:</u>
We have ,
,
We know that ![sin\alpha = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }](https://tex.z-dn.net/?f=sin%5Calpha%20%20%3D%20%5Cfrac%7BPerpendicular%7D%7BHypotenuse%7D%20%3D%20%5Cfrac%7BPerpendicular%7D%7B%5Csqrt%5B2%5D%7B%28Perpendicualr%29%5E%7B2%7D%20%2B%20%28Base%29%5E%7B2%7D%29%7D%20%7D)
Substituting values of P & B , 
Now , 
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×
×2
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The simplified form of that decimal in fraction form is 3/20. Hope this helps.
Answer:
59%
Step-by-step explanation: