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mart [117]
3 years ago
9

Between 10 P.M. and 7:45 A.M.​, the water level in a swimming pool decreased by 3/8 inches . Assuming that the water level decre

ased at a constant​ rate, how much did the water level drop each​ hour?
Mathematics
1 answer:
AVprozaik [17]3 years ago
5 0

Answer:

0.03846154... inches/hour

Step-by-step explanation:

between 10 P.M. and 7:45 A.M. = 9.75 hours

(3/8) inches / 9.75 hours = 0.03846154... inches per hour

EDIT: in fraction form

Answer:

1/26 inches/hour

Step-by-step explanation:

between 10 P.M. and 7:45 A.M. = 9 and 3/4 hours, or 39/4 hours

(3/8) inches / (39/4) hours = 1/26 inches per hour

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A ray of light passing from air through an equilateral glass prism undergoes minimum
Mama L [17]

Answer: 45° and speed of light in prism 2×10⁸m/s

Step-by-step explanation:

The minimum deviation of the equilateral glass prism will form 60° angle.

So angle of incidence = 3/4×60

= 3 ×15

= 45°

Minimum deviation = δmin

= 30

After finding the value of μ using prism law

μ = 1.41

Speed of light will be 2×10⁸m/s

Must click thanks and mark brainliest

5 0
2 years ago
HIGH POINT REWARD
Yuki888 [10]
Total number of seniors = 55 + 70 = 125
Number of seniors who plan to go to college = 55

Percentage of seniors who plan to go to college = 55/125 x 100 = 44%

Answer: 44%
3 0
3 years ago
The abdominopelvic region that is bordered by all four imaginary lines is the
Ainat [17]

Umbilical point.

An umbilic point, likewise called just an umbilic, is a point on a surface at which the arch is the same toward any path.

 

In the differential geometry of surfaces in three measurements, umbilics or umbilical focuses are focuses on a surface that are locally round. At such focuses the ordinary ebbs and flows every which way are equivalent, consequently, both primary ebbs and flows are equivalent, and each digression vector is a chief heading. The name "umbilic" originates from the Latin umbilicus - navel.

 

<span>Umbilic focuses for the most part happen as confined focuses in the circular area of the surface; that is, the place the Gaussian ebb and flow is sure. For surfaces with family 0, e.g. an ellipsoid, there must be no less than four umbilics, an outcome of the Poincaré–Hopf hypothesis. An ellipsoid of unrest has just two umbilics.</span>

4 0
3 years ago
State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle
DENIUS [597]

Answer:

The interval notation for the domain is [\frac{23}{3},\infty  ].

Step-by-step explanation:

Consider the provided information.

It is given that \:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7

We need to find the value of f\left(g\left(x\right)\right).

Put the value of g(x) in  f\left(g\left(x\right)\right).

f\left(g\left(x\right)\right)=f(x-7)  ....(1)

Now, put x=x-7 in \:f\left(x\right)=\sqrt{3x-2}

\:f\left(x-7\right)= \sqrt{3(x-7)-2}

\:f\left(x-7\right)= \sqrt{3x-21-2}

\:f\left(x-7\right)= \sqrt{3x-23}

From equation 1.

f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}

The domain of the function is the set of input values for which a function is defined.

Here, the value of 3x-23 should be greater or equal to 0 as the square root of a negative number is not real.

Domain= 3x-23\geq0

x\geq\frac{23}{3}

The value of x is all real number greater than \frac{23}{3}.

Hence, the interval notation for the domain is [\frac{23}{3},\infty  ].

7 0
2 years ago
Given g(x)=-2x-4find g(6)
Butoxors [25]

Answer:

g(6)=-16

Step-by-step explanation:

g(6)=-2(6)-4

g(6)=-12-4

g(6)=-16

Hope this helps lol

3 0
2 years ago
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