Ask question

Ask question

All categories

3 years ago

12

Determine the type and number of solutions of -4x^2-3x+7=0

1 answer:

IgorLugansk [536]3 years ago

8 0

-4x² <span>- 3x + 7 = 0
D = b</span>² -4ac = (-3)² - 4*(-4)*7 = 9 + 112 = 121
D>0 ⇒ <span>Two real solutions </span>

You might be interested in

The figure is made up of a semicircle and a rectangle.

dezoksy [38]

Area = Area of rectangle + area of semicircle

Area of rectangle = 5 x 1 = 5 m^2
area of semicircle = πD²/8 = 3.14 x 5² / 8 = 9. 8125
Area = 5 + 9.8125 = 14.8125 m^2

4 0

3 years ago

Consider a graph of the equation y = x + 6. What is the y-intercept?

Ratling [72]

In y = mx + b form, which is what ur equation is in, the y int can be found in the b position

y = mx + b
y = x + 6

as u can see, the number in the b position, ur y int, is 6 <==

7 0

3 years ago

aivan3 [116]

Answer:

Answer is A

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Henry planted 24 tomato plants and 18 green bean plants in his garden. Simon planted 30 tomato plants and 25 green bean plants i

jasenka [17]

Answer:

Its different.

Step-by-step explanation:

Henry's garden:

divide 24 and 18 by 6: you get 4:3 ratio of tomato:green bean

Simon's garden:

divide both 30 and 25 by 5: you get 6:5 ratio of tomato:green bean.

6 0

2 years ago

From a group of 8 women and 6 men, a committee consisting of 3 men and 3 women is to be formed. How many different committees ar

murzikaleks [220]

Answer:

(a) 896

(b) 1000

(c) 910

Step-by-step explanation:

Number of women = 8

Number of men = 6

A committee consisting of 3 men and 3 women is to be formed.

(a) 2 of the men refuse to serve together.

Number of men who don't want to serve together = 2

Remaining men = 4

Total ways = Both men who don't want to serve together are not selected + only one of them is selected.

$^{8}C_{3}\cdot ^{4}C_{3}+^{8}C_{3}\cdot ^{4}C_{2}\cdot ^{2}C_{1}$

$896$

(b) 2 of the women refuse to serve together.

Number of women who don't want to serve together = 2

Remaining men = 6

Total ways = Both women who don't want to serve together are not selected + only one of them is selected.

$^{6}C_{3}\cdot ^{6}C_{3}+^{6}C_{3}\cdot ^{6}C_{2}\cdot ^{2}C_{1}$

$1000$

(c)1 man and 1 woman refuse to serve together.

Ways = Total ways - Both man and woman are select who refuse the serve together

$^{8}C_{3}\cdot ^{6}C_{3}-^{5}C_{2}\cdot ^{7}C_{2}$

$910$

6 0

3 years ago