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2 years ago

What is the inverse of f (x) = 10 - X?

Mathematics

1 answer:

julsineya [31]2 years ago

5 0

Answer:

Step-by-step explanation:

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ROOTS AND CUBES Can someone please help me answer all 4 following?

Alex Ar [27]

NOTES:

squared (²) means multiply that number by itself 2 times
cubed (³) means multiply that number by itself 3 times
square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical

Answer: (C) 41

Step-by-step explanation:

$\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41$

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Answer: (C) 10

Step-by-step explanation:

$\bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}$

$=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}$

$=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9$

$=(7 - 2)\times \dfrac{1}{5}+9$

$=5 \times \dfrac{1}{5}+ 9$

$= 1 + 9$

$= 10$

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8² = 8 · 8 = 64 11² = 11 · 11 = 121

5³ = 5 · 5 · 5 = 125 3³ = 3 · 3 · 3 = 27

$\sqrt{1600}=\sqrt{40\cdot 40}=40$ $\sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4$

$\sqrt{144}=\sqrt{12\cdot 12}=12$ $\sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20$

3 0

3 years ago

In the standard (x, y) coordinate plane, if the x-coordinate of each point is 2 times the y-coordinate, what is the slope of the

uranmaximum [27]

1/2 (Rise over Run)
I hope this helps out :3

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3 years ago

Help me with this problem

ryzh [129]

Answer:

angle 1 = angle 3

= 180°-136°

=44°

= angle 3

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2 years ago

Which of the scatter plots below shows the most accurate line of best fit?

Marina86 [1]

I think its letter b

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2 years ago

X^2 +8 =0 please show all work

Virty [35]

$x^2+8=0\\
x^2=-8\\
x=-\sqrt{-8} \vee x=\sqrt{-8}\\
x=-\sqrt{8\cdot(-1)} \vee x=\sqrt{8\cdot(-1)}\\
x=-\sqrt{8}\cdot\sqrt{-1} \vee x=\sqrt{8}\cdot\sqrt{-1}\\
x=-\sqrt{4}\cdot \sqrt2\cdot i \vee x=\sqrt{4}\cdot \sqrt 2\cdot i\\
x=-2\sqrt{2}i \vee x=2\sqrt{2}i
$

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3 years ago