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3 years ago

13

a spinner is divided into eight equal parts numbered 1 to 8. if the spinner is spun once, what is the probability that it stops

on a number that is a multiple of 2?

2 answers:

emmasim [6.3K]3 years ago

7 0

Answer:

$\frac{1}{2}$ , which is 50% probability.

Step-by-step explanation:

The spinner equally divided into 8 parts and named as 1, 2, 3, 4, 5, 6, 7 and 8.

It is spun once, we need to find the probability of getting a number that is a multiple of 2.

Let's find the multiples of 2: 2, 4, 6, and 8

The total number favorable outcomes = 4

The number of possible outcomes = 8

The probability of an event = The number of favorable outcomes / The total number of possible outcomes.

Therefore, the probability that it stops on a number that is a multiple of 2 = $\frac{4}{8}$

When we simplify this fraction, we get

= $\frac{1}{2}$

Which is 50% probability.

Step2247 [10]3 years ago

4 0

Since the total number of available selections is divided by two, the probability is 50%. If we look at the total set of numbers, we find that even numbers are multiples of 2. 2, 4, 6, 8 (which makes up half of the numbers on the spinner).

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How to answer this on descending powers of x please help pretty please

zheka24 [161]

Answer: 25x² - 64

<u>Step-by-step explanation:</u>

(5x + 8)(5x - 8)

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= 25x² - 40x + 40x - 64

= 25x² + 0x - 64

= $\large\boxed{25x^2-64}$

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For example: x⁴ then x³ then x² then x then the number (which is actually x⁰)

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3 years ago

a bird is flying at a true bearing of 75 degree's at a speed of 40 miles per hour. Write the velocity of the bird as a vector in

Allisa [31]

Answer: V = (10.4 mph, 38.6 mph)

Step-by-step explanation:

The velocity is written as (vx, vy)

where vx is the component of the velocity in the x-axis and vy is the component of the velocity in the y-axis.

In usual notation, the angles are measured counterclockwise from the positive x-axis.

We know that the angle is 75°, this means that the velocity in the x-axis will be equal to the total velocity of the bird projected in the x-axis (suppose a triangle rectangle, where the velocity is the hypotenuse, the x component is a cathetus and the y component is other cathetus)

vx = 40mph*cos(75°) = 10.4 mph

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Then the vector of velocity is V = (10.4 mph, 38.6 mph)

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3 years ago

five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. what is the solution

Marrrta [24]

5(x + 27) >= 6(x + 26)

5x + 135 >= 6x + 156

-x >= 21

x <= -21

Answer: Choice B.

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3 years ago

Read 2 more answers

Special right triangles.

Oliga [24]

QUESTION 9

The given right angle triangle has its two legs equal to $x\:cm$ and the hypotenuse is $2\:units$ .

Using the Pythagoras theorem, we have

$x^2+x^2=2^2$

This implies that;

$2x^2=2^2$

$2x^2=4$

$x^2=2$

$x=\sqrt{2}$

$x=1.414$

$x\approx1.4\:units$

QUESTION 10

The given right angle triangle has its two legs equal to $x\:units$ and the hypotenuse is $7\:units$ .

Using the Pythagoras theorem, we have

$x^2+x^2=7^2$

This implies that;

$2x^2=7^2$

$2x^2=49$

$x^2=24.5$

$x=\sqrt{24.5}$

$x=4.95\:units$

QUESTION 11

Sam divided the square backyard into two sections along the 40ft diagonal.

Let one of the sides of the garden be $x\:units$ , then the other side of the garden is also $x\:units$ since it was a square backyard.

The diagonal is the hypotenuse which is 40ft and the two legs are $x\:units$ each.

Applying the Pythagoras Theorem, we have;

$x^2+x^2=40^2$

$2x^2=1600$

$x^2=800$

$\Rightarrow x=\sqrt{800}$

$\Rightarrow x=28.28$

The length of one side of the garden is approximately 28cm.

QUESTION 12

The hypotenuse of Nicole's right triangular support is 92cm long.

It was given that the two lengths of the triangular support are of equal length.

Let the two lengths of the triangular support be $l\:cm$ each.

We then apply the Pythagoras theorem to obtain;

$l^2+l^2=92^2$

$\Rightarrow 2l^2=8464$

$\Rightarrow l^2=4232$

$\Rightarrow l=\sqrt{4232}$

$\Rightarrow l=65.05cm$

Therefore Nicole needs $l+l=65.05cm+65.05cm\approx130cm$ of wood to complete the support.

The correct answer is A.

QUESTION 13

A 45-45-90 triangle is an isosceles right triangle.

Let the length of the two legs be $m\:inches$ each.

It was given that the hypotenuse of this triangle is $12\:inches$ .

Applying the Pythagoras Theorem, we have;

$m^2+m^2=12^2$

$\Rightarrow 2m^2=144$

$\Rightarrow m^2=72$

$\Rightarrow m=\sqrt{72}$

$\Rightarrow m=8.49$

The length of one leg of the hypotenuse is approximately 8.5 inches to 1 decimal place.

QUESTIONS 14.

It was given that the distance from home plate to first base is 90 feet.

Since the baseball field form a square, the length of the baselines are all 90ft.

We want to calculate the distance from home plate to 2nd base,which is the diagonal of the square baseball field.

Let this distance be $d\:ft$ , then using the Pythagoras theorem;

$d^2=90^2+90^2$

$d^2=8100+8100$

$d^2=16200$

$\:d=\sqrt{16200}$

$\:d=127.279$

Therefore the distance from home plate to second base is 127 ft to the nearest foot.

QUESTION 15.

The distance from third base to first base is also 127 ft to the nearest foot.

The reason is that the diagonals of a square are equal in length.

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3 years ago

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nydimaria [60]

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3 years ago