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3 years ago

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Mr.Lash has 42 pounds of dog food divide among his dogs. If each dog receives 7/8 pound of food for each feeding, how many times

CV an Mr.Lash feed his animals?

1 answer:

igor_vitrenko [27]3 years ago

4 0

Answer:

48 times

Step-by-step explanation:

(42 pounds)/(7/8 pounds/feeding) = 42·(8/7) feedings = 48 feedings

Mr Lash can feed 48 meals to his animals.

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Please help i cant fail

Ira Lisetskai [31]

Answer:

3a+13

Step-by-step explanation:

Add 5 and 8 together to get 13

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3 years ago

A full-service salon charges $15.00 for a haircut and $0.45 per hair roller used in a perm. What is the minimum number of hair r

IrinaK [193]

Answer:

43 hair rollers.

Step-by-step explanation:

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3 years ago

Y is the midpoint of segment XZ. The coordinates of X are (2, 4) and of Y are (-1, 1). Find the coordinates of Z. ...?

Elenna [48]

Given x(x1,y1)=(2,4)
z(x2,y2)=(x2,y2)
midpoint (x,y)=(-1,1)
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2+x2=-2;4+y2=2
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7 0

4 years ago

Read 2 more answers

Order the numbers from least to greatest: -7/8, 7/4, -15/2, and -13/16

VikaD [51]

-13/16; -7/8; -15/2; 7/4 hope i helped good luck on ur exam :)

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3 years ago

On average, Tanner has noticed that 22 trains pass by his house daily (24 hours) on the nearby train tracks. What is the probabi

blondinia [14]

Answer:

0.11069

Step-by-step explanation:

We will assume that the trains pass by his house following a uniform distribution with values between 0 and 24. The probability of a train passing on a 9-hour time period is 9/24 = 3/8 = 0.375. Lets call Y the amount of trains passing by his house during that 9-hour period. Y follows a Binomail distribution with parameters 22 and 0.375.

P(Y ≤ 5) = P(Y = 0) + P(Y=1) + P(Y=2) + P(Y=3) + P(Y=4) + P(Y=5) =

${22 \choose 0} * 0.375^0*(1-0.375)^{22} + {22 \choose 1}*0.375^1*(1-0.375)^{21} +\\\\{22 \choose 2} * 0.375^2*(1-0.375)^{20} + {22 \choose 3}*0.375^3*(1-0.375)^{19} + \\{22 \choose 4} * 0.375^4*(1-0.375)^{18} + {22 \choose 5}*0.375^5*(1-0.375)^{17} = 0.11069$

I hope that works for you!

4 0

3 years ago