Step-by-step explanation:
H0: u = 44.3
Hi : u# 44.3
Z1-0.05/2
Z1-0.025
Z0.975 = 1.96
Z = x-u/s.d/√n
Z= 44.4 -44.3/2.6/√130
Z = (0.1×11.4018)/2.6
Z=0.44
Since the calcalculated value is less than the table value and does not fall in the rejection region we fail to reject the null hypothesis
Answer:
Choice A: there is insufficient evidence to conclude that the mean for the fiber content is less than 2.5 gms.
Step-by-step explanation:
From the graphs given the more appropriate is one sample t- test
One sample t- test is used and the results are
Hypothesis Test Fiber
Sample Mean 2.62
Sample St. Dev 3.492
Degrees of Freedom 24
t- test statistic 0.1718
p- value 0.5675
the critical region for this test at ∝= 0.05 is t < -1.711
There is not enough evidence to reject the null hypothesis.
Since the calculated t= 0.1718 does not fall in the critical region the null hypothesis is accepted that the mean fiber content is not less than 2.5 grams.T
Answer:
he mean, mode and median are all equal. The curve is symmetric at the center (i.e. around the mean, μ). Exactly half of the values are to the left of center and exactly half the values are to the right. The total area under the curve is 1.
Step-by-step explanation:
