Your question does not say what were your options, therefore I will answer generically: in order to understand if a point (ordered pair) is contained in a line, you need to substitute the x-component of the pair in the equation of the line and see if the calculations give you the y-component of the pair.
Example:
Your line is <span> y = 4/3x + 1/3
Let's see if <span>(0, 0) and (2, 3) </span>belong to this line
y</span> = <span>4/3·0 + 1/3 = 1/3 </span>≠ 0
Therefore, the line does not contain (0, 0)
y = 4/3·2 + 1/3 = 9/3 = 3
Therefore, the line contains (2, 3)
Answer:
The constant of proportionality in the equation y=0.41 is 0.41
Step-by-step explanation:
Answer:
- 13x² - 19x + 23
- -16x +17
Step-by-step explanation:
1 . (4x² - 9x + 16) + (7 + 9x² - 10x)
4x² - 9x + 16 + 7 + 9x² - 10x
13x² - 19x + 23
2 . (-2x + 6) - (14x - 11)
-2x + 6 - 14x + 11
-16x +17
Add them up and you have your answer
Since in a pass code, the placement of the digits is
important, therefore this means that to solve for the total number of
possibilities we have to make use of the principle of Permutation. The formula
for calculating the total number of possibilities using Permutation is given
as:
P = n! / (n – r)!
where,
n = is the total amount of numbers to choose from = 20
r = is the total number of digits needed in the passcode =
4
Therefore solving for the total possibilities P:
P = 20! / (20 – 4)!
P = 20! / 16!
P = 116,280
<span>Hence there are a total of 116,280 possibilities of pass
codes.</span>