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Helen [10]
3 years ago
7

Please answer i need help

Mathematics
2 answers:
skad [1K]3 years ago
8 0
1. 72 to 50 points
50/72 = 69%
100-69= 31% decrease

2. 14 to 40 books
14 / 40 = 35%
100-35= 65% increase

3. 10 plus 30% increase
10 * 0.3 = 13
scoray [572]3 years ago
5 0
1 can someone help me
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If line A contains Q(5,1) and is parallel to line MN with M(-2,4) and N(2,1), which ordered pair would be on the perpendicular t
vivado [14]
Your question does not say what were your options, therefore I will answer generically: in order to understand if a point (ordered pair) is contained in a line, you need to substitute the x-component of the pair in the equation of the line and see if the calculations give you the y-component of the pair.

Example:
Your line is <span> y = 4/3x + 1/3
Let's see if <span>(0, 0) and (2, 3) </span>belong to this line

y</span> = <span>4/3·0 + 1/3 = 1/3 </span>≠ 0
Therefore, the line does not contain (0, 0)

y = 4/3·2 + 1/3 = 9/3 = 3
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6 0
3 years ago
Read 2 more answers
What is the constant of posprtainality in the equation y=0.41
KATRIN_1 [288]

Answer:

The constant of proportionality in the equation y=0.41 is 0.41

Step-by-step explanation:

5 0
3 years ago
I need help with both of these
jeka57 [31]

Answer:

  1. 13x² - 19x + 23
  2. -16x +17

Step-by-step explanation:

1 . (4x² - 9x + 16) + (7 + 9x² - 10x)

4x² - 9x + 16 + 7 + 9x² - 10x

13x² - 19x + 23

2 . (-2x + 6) - (14x - 11)

-2x + 6 - 14x + 11

-16x +17

8 0
3 years ago
What is the size of ABC?
11Alexandr11 [23.1K]
Add them up and you have your answer
3 0
3 years ago
If you are allowed to use numbers 1 – 20 and need to choose the passcode of an exact 4 digit code, how many possibilities are th
VMariaS [17]

Since in a pass code, the placement of the digits is important, therefore this means that to solve for the total number of possibilities we have to make use of the principle of Permutation. The formula for calculating the total number of possibilities using Permutation is given as:

P = n! / (n – r)!

where,

n = is the total amount of numbers to choose from = 20

r = is the total number of digits needed in the passcode = 4

 

Therefore solving for the total possibilities P:

P = 20! / (20 – 4)!

P = 20! / 16!

P = 116,280

 

<span>Hence there are a total of 116,280 possibilities of pass codes.</span>

4 0
3 years ago
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