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padilas [110]
3 years ago
5

4 2/5 x 2 2/3 PLSS I NEED IT RN!!

Mathematics
1 answer:
vlabodo [156]3 years ago
4 0

Answer: 10.92

Step-by-step explanation: Transforming the mixed fractions makes 4.2 and 2.6, which which when multiplied would give you 10.92.

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An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
cos(2arctan( \sqrt{2} ))= \frac{-1}{3} 

substituting our second soultion we get
I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
so the maximum value =\frac{1}{3}
minimum value =- \frac{1}{3}


4 0
3 years ago
Simplify as far as possible.<br> 2√125−5√5
sveticcg [70]

Answer:

5

Step-by-step explanation:

Simplify (-10- square root of 125)/5. −10−√1255 - 10 - 125 5. Simplify the numerator.

8 0
3 years ago
Read 2 more answers
There are 970 students in bayton high school. Brian takes a random sample of 100 students. He asks these 100 students which subj
Pani-rosa [81]

Answer:

How to do the estimation

Step-by-step explanation:

He can use the probability of how many people chose English and multiply by 9.7 since there are 970 people / 100 people who asked = 9.7

7 0
3 years ago
(no links or files) Solve this equation using the quadratic formula. This question should be solved both ways. (1) Quadratic For
meriva
Quadratic formula is x = -b+ or- sq rt b^2-4ac / 2a
a=2 b=5 c=-3
-5 +or- sqrt 5^2-4(2)(-3) / 2(2)
-5 +or- sqrt 49/ 4
-5 + 7 /4 = 2/4 = 1/2
-5 - 7 /4 = -12/4 = -3

Factoring a*c is 2*-3 =-6
Factors of -6 that add to 5 are 6 and -1
Split 5x into +6x-1x
2x^2+6x-1x-3 and group
2x(x+3)-1(x+3)
(x+3)(2x-1)=0
x+3=0 gives x=-3
2x-1=0 gives x=1/2
4 0
3 years ago
Solve for the balloon volume using the equation below
valentinak56 [21]

The volume of the balloon is 1441.64cm³.

<h3>How to calculate the volume?</h3>

The radius of the balloon is given as 7cm. Also, the equation to calculate the volume is given as c³/6π²

The circumference c will be:

= 2πr = 2 × 22/7 × 7

= 44

The volume will be:

= c³/6π²

= 44³/(6 × 3.14²)

= 85284/(59.1576)

= 1441.64

Learn more about volume on:

brainly.com/question/1972490

#SPJ1

3 0
2 years ago
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