T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
A quarter coin is half in value of a half-dollar coin. Therefore, two quarters makes up each half dollar coin.
Now, we know that Jessie has 14 half-dollar coins, but she needs quarters to do her laundry. Thus, if each half-dollar coin gives two quarters then 14 half-dollar coins will give quarters.
Thus, if Jessie trades all her 14 half-dollar coins for quarters, she will have 28 quarters for her laundry.
washer + dryer = 1104
dryer = x
washer = 3x
3x + x = 1104
4x= 1104
x = 276 = dryer
washer = 3x = 3(276)= 828
I HOPE I HELPED YOU ;)
Answer:The domain of
=
R
−
{
3
}
The range of
=
R
−
{
2
}
Step-by-step explanation: