Solve each inequality. Then compare the solutions. 3x +4> 16 - 2x + 19< 11

Mathematics

1 answer:

Makovka662 [10]3 years ago

7 0

Answer:

$3x + 4 > 16 \\ 3x > 16 - 4 \\ \frac{3x}{3} > \frac{12}{3} \\ x > 4 \\ \\ - 2x + 19 < 11 \\ - 2x < 11 - 19 \\ - 2x < - 8 \\ \frac{ - 2x}{ - 2} > \frac{ - 8}{ - 2} \\ x > 4 \\ \\ comparing \\ 4 < x > 4$

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