To solve this polynomial equation, we first factor the left side.
To factor x² + 8x + 12 = 0, look for factors of 12 that add to 8.
These factors are 6 and 2 so we have (x + 6)(x + 2) = 0.
So either x + 6 = 0 or x + 2 = 0 and solving for
x in each equation, our answer is {-6, -2}.
4/5 is the the fraction of a pound is eighty pence
No, 2v times v is not 2v
2v*v is 2v^2
1) For a quadratic equation, we'll have two answers typically. We're looking for two numbers that when multiplied give -64, and when added give -12. This is a bit of trial and error, but you go about it by systematically factoring -64 in all possible combinations: 64=-2*32=2*-32=-4*16=4*-16=-8*8. Of these, I can 'see' that I can make -12 with 4 and -16. So the factorization of the equation becomes:
(x-16)(x+4)=0, so x=16 or x=-4.
Answers B and D are correct.
For (2), same trick applies. Rewrite as x²-8x-48=0. Factor as (x+4)(x-12)=0 because 4*-12=-48 and 4-12=-8. The other solution is x=12.
