a. Let be a random variable representing the weight of a ball bearing selected at random. We're told that , so
where . This probability is approximately
b. Let be a random variable representing the weight of the -th ball that is selected, and let be the mean of these 4 weights,
The sum of normally distributed random variables is a random variable that also follows a normal distribution,
so that
Then
c. Same as (b).
After 4 hours there will be 64 000
3 - 32k
2-16
1-8
do you need exactly 50 000?
Answer:
Jenny=$16
Austin=$32
Chang=$16
Step-by-step explanation:
-let the amount Chang has be x.
-Therefore, each individuals amount is expressed as:
We equate the sum of their amounts to $73 to solve for x;
#Austin's amount is therefore:
Chang's amount is $16
Jenny's amount=x+9=16+9=$25
Answer:
9 hours
Step-by-step explanation: