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3 years ago

Given that 6 yards is equal to 18 feet, what is the ratio of yards to fee

Mathematics

1 answer:

expeople1 [14]3 years ago

3 0

I'm going to assume you just mean how do you write the ratio, in which case the answers vary
18:6
18 to 6
or
18/6

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What is the value of this expression when c=-4 and d = 10?<br> 1/4(c3+d2)

Mumz [18]

What is the value of this expression when c = -4 and d = 10 ? $\frac{1}{4}$ (c³ + d²)

<h3>Given:-</h3>

$\frac{1}{4}$ (c³ + d²) where c = -4 and d = 10

The value of the expression $\frac{1}{4}$ (c³ + d²)

<h2>Solution:-</h2>

$\frac{1}{4}$ (c³ + d²) [Given expression]

Now, putting the value of c = -4 and d = 10 , we get,

$\frac{1}{4}$ { (-4)³ + (10)² }

$\frac{1}{4}$ ( -64 + 100 )

$\frac{1}{4}$ ( 36 )

$\frac{1}{4}$ × 36

$\bf = \: 9 \: ( Answer )$

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3 years ago

What is the difference between 85.23 and 2.675

Vinil7 [7]

Answer:

82.555

Step-by-step explanation:

Based on the given conditions, formulate:

85.23 - 2.675

Calculate the sum or difference: 82.555

5 0

2 years ago

A scale drawing of an NFL god post uses a

Alex17521 [72]

It would be 455 inches because you divide 5/2 and it is 2.5 then you multiply it by 182 which is 455

6 0

3 years ago

Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years. A study wa

4vir4ik [10]

Using the z-distribution, it is found that since the <u>test statistic is greater than the critical value</u>, it can be concluded that the mean length of jail time has increased.

At the null hypothesis, it is <u>tested if the mean length of jail time is still of 2.5 years</u>, that is:

$H_0: \mu = 2.5$

At the alternative hypothesis, it is <u>tested if it has increased</u>, that is:

$H_1: \mu > 2.5$

We have the <u>standard deviation for the population</u>, thus, the z-distribution is used. The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
$\sigma$ is the standard deviation of the sample.
n is the sample size.

For this problem, the values of the <u>parameters</u> are: $\overline{x} = 3, \mu = 2.5, \sigma = 1.5, n = 26$

Hence, the value of the <u>test statistic</u> is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{3 - 2.5}{\frac{1.5}{\sqrt{26}}}$

$z = 1.7$

The critical value for a <u>right-tailed test</u>, as we are testing if the mean is greater than a value, with a <u>significance level of 0.05</u>, is of $z^{\ast} = 1.645$

Since the <u>test statistic is greater than the critical value</u>, it can be concluded that the mean length of jail time has increased.

A similar problem is given at brainly.com/question/24166849

5 0

2 years ago

What is the Approximate the value of √30

Nina [5.8K]

5.47722558 is the answer

3 0

3 years ago

Read 2 more answers