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2 years ago

9

Laura tiene una tarifa de telefono en la que paga solo por el tiempo que dura cada llamada .Si un minuto cuesta o,16€ ysu ultima

llamada duro 3,15 min ¿cuanto tendra que pagar?

1 answer:

Evgesh-ka [11]2 years ago

7 0

Answer:

50,4 €

Step-by-step explanation:

De la pregunta anterior,

1 minuto = 16 €

3,15 minutos = x

Cruz multiplicar

x × 1 minuto = 16 € × 3,15 minutos

x = € 16 × 3,5 minutos / 1 minuto

x = 50,4 €

Por tanto, por una llamada de 3,15 minutos, Laura tendrá que pagar 50,4 €.

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Graph y = 4x - 1. When x = -2, what is the ordered pair of the solution?

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You want to estimate the mean amount of time college students spend on the Internet each month. How many college students must y

KonstantinChe [14]

Answer:

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Step-by-step explanation:

Data provided in the question

The standard deviation of population = 210

The Margin of error = 15

The confidence level is 75%, so the z value is 1.96

Now the required sample size is

$= 1.96^2\times \frac{210^2}{15^2}$

= 752.95

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3 years ago

Roll the number cube to find the observed frequency. Which statements are true? Check all that apply

ch4aika [34]

Answer:

(a) and (c)

Step-by-step explanation:

Given

See attachment for complete question

Required

Select all true statements

First, calculate the total observed frequency;

$Total = 11 + 16 + 14 + 20 + 12 + 17$

$Total = 90$

<u>(a): Relative frequency of 4 is 2/9</u>

Relative frequency is calculated by:

$RF= \frac{Observed\ Frequency}{Total}$

For roll 4

$Observed\ frequency = 20$

So, the relative frequency is:

$RF = \frac{20}{90}$

Simplify

$RF = \frac{2}{9}$

<em>(a) is true</em>

<u>(b): Experimental probability of 3 greater than its theoretical probability</u>

The experimental probability is its relative frequency;

For roll 3

$Observed\ frequency = 14$

The experimental probability is:

$Pr = \frac{14}{90}$

Simplify

$Pr = \frac{7}{45} = 0.156$

To calculate the theoretical probability, w have:

$S = \{1,2,3,4,5,6\}$ ---- sample space

$n(S)= 6$

$n(3) = 1$ --- number of times 3 occur

The theoretical probability is:

$Pr = \frac{1}{6} = 0.167$

The theoretical probability is $greater\ than\ the$ experimental probability.

<em>(b) is false</em>

<u>(c): Experimental probability of 2 greater than its theoretical probability</u>

Using the explanations in (b), we have:

For roll 2

$Observed\ frequency = 16$

The experimental probability is:

$Pr = \frac{16}{90}$

Simplify

$Pr = \frac{8}{45} = 0.178$

To calculate the theoretical probability, we have:

$n(S)= 6$

$n(2) = 1$

The theoretical probability is:

$Pr = \frac{1}{6} = 0.167$

The experimental probability is $greater\ than\ the$ theoretical probability.

<em>(c) is true</em>

<u>(d): Relative frequency of 5 is 2/13</u>

For roll 5

$Observed\ frequency = 12$

The relative frequency is:

$RF = \frac{12}{90}$

Simplify

$RF = \frac{2}{15}$

<em>(d) is true</em>

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2 years ago