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Effectus [21]
3 years ago
7

Camila Cabello wants to order cheesecakes over the internet. Each cheesecake costs $15.99 and shipping for the entire order is

Mathematics
1 answer:
ladessa [460]3 years ago
6 0

Answer:

she can purchase 5 cheesecakes

Step-by-step explanation:

15.99*5=79.95

if we add 9.99 for the shipping of thw whole order

79.95+9.99=89.94

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3 years ago
Differential Equation
ANEK [815]

1. The given equation is probably supposed to read

y'' - 2y' - 3y = 64x exp(-x)

First consider the homogeneous equation,

y'' - 2y' - 3y = 0

which has characteristic equation

r² - 2r - 3 = (r - 3) (r + 1) = 0

with roots r = 3 and r = -1. Then the characteristic solution is

y = C_1 e^{3x} + C_2 e^{-x}

and we let y₁ = exp(3x) and y₂ = exp(-x), our fundamental solutions.

Now we use variation of parameters, which gives a particular solution of the form

y_p = u_1y_1 + u_2y_2

where

\displaystyle u_1 = -\int \frac{64xe^{-x}y_2}{W(y_1,y_2)} \, dx

\displaystyle u_2 = \int \frac{64xe^{-x}y_1}{W(y_1,y_2)} \, dx

and W(y₁, y₂) is the Wronskian determinant of the two fundamental solutions. This is

W(y_1,y_2) = \begin{vmatrix}e^{3x} & e^{-x} \\ (e^{3x})' & (e^{-x})'\end{vmatrix} = \begin{vmatrix}e^{3x} & e^{-x} \\ 3e^{3x} & -e^{-x}\end{vmatrix} = -e^{2x} - 3e^{2x} = -4e^{2x}

Then we find

\displaystyle u_1 = -\int \frac{64xe^{-x} \cdot e^{-x}}{-4e^{2x}} \, dx = 16 \int xe^{-4x} \, dx = -(4x + 1) e^{-4x}

\displaystyle u_2 = \int \frac{64xe^{-x} \cdot e^{3x}}{-4e^{2x}} \, dx = -16 \int x \, dx = -8x^2

so it follows that the particular solution is

y_p = -(4x+1)e^{-4x} \cdot e^{3x} - 8x^2\cdot e^{-x} = -(8x^2+4x+1)e^{-x}

and so the general solution is

\boxed{y(x) = C_1 e^{3x} + C_2e^{-x} - (8x^2+4x+1) e^{-x}}

2. I'll again assume there's typo in the equation, and that it should read

y''' - 6y'' + 11y' - 6y = 2x exp(-x)

Again, we consider the homogeneous equation,

y''' - 6y'' + 11y' - 6y = 0

and observe that the characteristic polynomial,

r³ - 6r² + 11r - 6

has coefficients that sum to 1 - 6 + 11 - 6 = 0, which immediately tells us that r = 1 is a root. Polynomial division and subsequent factoring yields

r³ - 6r² + 11r - 6 = (r - 1) (r² - 5r + 6) = (r - 1) (r - 2) (r - 3)

and from this we see the characteristic solution is

y_c = C_1 e^x + C_2 e^{2x} + C_3 e^{3x}

For the particular solution, I'll use undetermined coefficients. We look for a solution of the form

y_p = (ax+b)e^{-x}

whose first three derivatives are

{y_p}' = ae^{-x} - (ax+b)e^{-x} = (-ax+a-b)e^{-x}

{y_p}'' = -ae^{-x} - (-ax+a-b)e^{-x} = (ax-2a+b)e^{-x}

{y_p}''' = ae^{-x} - (ax-2a+b)e^{-x} = (-ax+3a-b)e^{-x}

Substituting these into the equation gives

(-ax+3a-b)e^{-x} - 6(ax-2a+b)e^{-x} + 11(-ax+a-b)e^{-x} - 6(ax+b)e^{-x} = 2xe^{-x}

(-ax+3a-b) - 6(ax-2a+b) + 11(-ax+a-b) - 6(ax+b) = 2x

-24ax+26a-24b = 2x

It follows that -24a = 2 and 26a - 24b = 0, so that a = -1/12 = -12/144 and b = -13/144, so the particular solution is

y_p = -\dfrac{12x+13}{144}e^{-x}

and the general solution is

\boxed{y = C_1 e^x + C_2 e^{2x} + C_3 e^{3x} - \dfrac{12x+13}{144} e^{-x}}

5 0
3 years ago
Dajuan is painting a mural on a rectangular
horsena [70]

Answer:

Every day Dajuan will paint 14.5 square feet of the wall.

Step-by-step explanation:

Since Dajuan is painting a mural on a rectangular wall, which measures 14.5 feet long and 10 feet wide, and so far, his mural covers 60% of the wall, and Dajuan will paint the remaining part of the wall over the next four days, painting the same amount of the wall, in square feet, on each of those four days, to determine how much of the wall, in square feet, will Dajuan paint on each of the next four days, the following calculation must be performed:

((14.5 x 10) x 0.4) / 4 = X

(145 x 0.4) / 4 = X

58/4 = X

14.5 = X

Therefore, every day Dajuan will paint 14.5 square feet of the wall.

4 0
3 years ago
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