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Zarrin [17]
3 years ago
13

For which system of equations is the graph below a solution?

Mathematics
1 answer:
iris [78.8K]3 years ago
8 0
Answer: B


Step by step explanation: trust me dawg
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A missing fraction on a number line is located exactly half way between 3/6 and 5/6
fomenos
The missing fraction on the number line would be 4/6.
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4 years ago
An experimenter flips a coin 100 times and gets 59 heads. Find the 98% confidence interval for the probability of flipping a hea
lara [203]

Answer:

The 98% confidence interval for the probability of flipping a head with this coin is (0.4756, 0.7044).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

An experimenter flips a coin 100 times and gets 59 heads.

This means that n = 100, \pi = \frac{59}{100} = 0.59

98% confidence level

So \alpha = 0.02, z is the value of Z that has a p-value of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.59 - 2.327\sqrt{\frac{0.59*0.41}{100}} = 0.4756

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.59 + 2.327\sqrt{\frac{0.59*0.41}{100}} = 0.7044

The 98% confidence interval for the probability of flipping a head with this coin is (0.4756, 0.7044).

5 0
3 years ago
For kids party of africa, it is also a way to get clean water to their communities. How? The merry-go-rounds pump water out of t
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Read 2 more answers
You have a chess board as pictured, with squares numbered 1 through 64. You also have a huge change jar with an unlimited number
ANEK [815]

Answer:

(a) 512 dimes

(b)D(n) = 2^{n-1}

(c) 9.22337 x 10¹⁸ dimes

(d) 9.22337 x 10¹² km

(e) roughly 61,489.13 times longer than the distance from the earth to the sun.

Step-by-step explanation:

b. Starting with 1 dime in the first square, if the number of dimes per each square is the double of the previous square, the general equation for the number of dimes in each square 'n' can be found by:

D(1) = 1\\D(2) = 2^1\\D(3) = 2^2\\D(4) = 2^3\\D(n) = 2^{n-1}

a. On the 10th square:

D(10) = 2^{10-1}\\D(10) = 512\ dimes

c. On the 64th square:

D(64) = 2^{64-1}\\D(10) = 9.22337 *10^{18}\ dimes

d. If a dime is 1 mm thick, the 64th pile will be:

h= 9.22337*10^{18}*0.0001\ m\\h= 9.22337*10^{15}\ m\\h= 9.22337*10^{12}\ km

e. The ratio between the height of the last pile (h) to the distance from the earth to the sun is:

R=\frac{9.22337*10^{12}\ km}{150,000,000\ km}\\ R=61,489.13

The height of the last pile is roughly 61,489.13 times longer than the distance from the earth to the sun.

5 0
3 years ago
ILL GIVE BRAINLIEST IF ITS THE FIRST CORRECT
Elza [17]

Step-by-step explanation:

zero is sea level, points above are above sea level and the points below are below sea level, I believe

6 0
3 years ago
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